rgb-cln/daemon/channel.c

244 lines
6.7 KiB
C
Raw Normal View History

#include "channel.h"
#include "htlc.h"
#include "remove_dust.h"
#include <assert.h>
#include <ccan/array_size/array_size.h>
#include <ccan/mem/mem.h>
#include <ccan/structeq/structeq.h>
#include <string.h>
uint64_t fee_by_feerate(size_t txsize, uint32_t fee_rate)
{
/* BOLT #2:
*
* The fee for a transaction MUST be calculated by multiplying this
* bytecount by the fee rate, dividing by 1000 and truncating
* (rounding down) the result to an even number of satoshis.
*/
return txsize * fee_rate / 2000 * 2;
}
static uint64_t calculate_fee_msat(size_t num_nondust_htlcs,
uint32_t fee_rate)
{
uint64_t bytes;
/* BOLT #2:
*
* A node MUST use the formula 338 + 32 bytes for every
* non-dust HTLC as the bytecount for calculating commitment
* transaction fees. Note that the fee requirement is
* unchanged, even if the elimination of dust HTLC outputs has
* caused a non-zero fee already.
*/
bytes = 338 + 32 * num_nondust_htlcs;
/* milli-satoshis */
return fee_by_feerate(bytes, fee_rate) * 1000;
}
/* Pay this much fee, if possible. Return amount unpaid. */
static uint64_t pay_fee(struct channel_oneside *side, uint64_t fee_msat)
{
if (side->pay_msat >= fee_msat) {
side->pay_msat -= fee_msat;
side->fee_msat += fee_msat;
return 0;
} else {
uint64_t remainder = fee_msat - side->pay_msat;
side->fee_msat += side->pay_msat;
side->pay_msat = 0;
return remainder;
}
}
/* Charge the fee as per BOLT #2 */
static void recalculate_fees(struct channel_oneside *a,
struct channel_oneside *b,
uint64_t fee_msat)
{
uint64_t remainder;
/* Fold in fees, to recalcuate again below. */
a->pay_msat += a->fee_msat;
b->pay_msat += b->fee_msat;
a->fee_msat = b->fee_msat = 0;
/* BOLT #2:
*
* 1. If each nodes can afford half the fee from their
* to-`final_key` output, reduce the two to-`final_key`
* outputs accordingly.
*
* 2. Otherwise, reduce the to-`final_key` output of one node
* which cannot afford the fee to zero (resulting in that
* entire output paying fees). If the remaining
* to-`final_key` output is greater than the fee remaining,
* reduce it accordingly, otherwise reduce it to zero to
* pay as much fee as possible.
*/
remainder = pay_fee(a, fee_msat / 2) + pay_fee(b, fee_msat / 2);
/* If there's anything left, the other side tries to pay for it. */
remainder = pay_fee(a, remainder);
pay_fee(b, remainder);
}
/* a transfers htlc_msat to a HTLC (gains it, if -ve) */
static bool change_funding(uint64_t anchor_satoshis,
uint32_t fee_rate,
int64_t htlc_msat,
struct channel_oneside *a,
struct channel_oneside *b,
size_t num_nondust_htlcs)
{
uint64_t fee_msat;
uint64_t htlcs_total;
htlcs_total = anchor_satoshis * 1000
- (a->pay_msat + a->fee_msat + b->pay_msat + b->fee_msat);
fee_msat = calculate_fee_msat(num_nondust_htlcs, fee_rate);
/* If A is paying, can it afford it? */
if (htlc_msat > 0) {
if (htlc_msat + fee_msat / 2 > a->pay_msat + a->fee_msat)
return false;
}
/* OK, now adjust funds for A, then recalculate fees. */
a->pay_msat -= htlc_msat;
recalculate_fees(a, b, fee_msat);
htlcs_total += htlc_msat;
assert(htlcs_total == anchor_satoshis * 1000
- (a->pay_msat + a->fee_msat + b->pay_msat + b->fee_msat));
return true;
}
struct channel_state *initial_cstate(const tal_t *ctx,
uint64_t anchor_satoshis,
uint32_t fee_rate,
enum channel_side funding)
{
uint64_t fee_msat;
struct channel_state *cstate = talz(ctx, struct channel_state);
struct channel_oneside *funder, *fundee;
cstate->fee_rate = fee_rate;
cstate->anchor = anchor_satoshis;
cstate->num_nondust = 0;
/* Anchor must fit in 32 bit. */
if (anchor_satoshis >= (1ULL << 32) / 1000)
return tal_free(cstate);
fee_msat = calculate_fee_msat(0, fee_rate);
if (fee_msat > anchor_satoshis * 1000)
return tal_free(cstate);
funder = &cstate->side[funding];
fundee = &cstate->side[!funding];
/* Neither side has HTLCs. */
funder->num_htlcs = fundee->num_htlcs = 0;
/* Initially, all goes back to funder. */
funder->pay_msat = anchor_satoshis * 1000 - fee_msat;
funder->fee_msat = fee_msat;
/* Make sure it checks out. */
assert(change_funding(anchor_satoshis, fee_rate, 0, funder, fundee, 0));
assert(funder->fee_msat == fee_msat);
assert(fundee->fee_msat == 0);
return cstate;
}
void adjust_fee(struct channel_state *cstate, uint32_t fee_rate)
{
uint64_t fee_msat;
fee_msat = calculate_fee_msat(cstate->num_nondust, fee_rate);
recalculate_fees(&cstate->side[OURS], &cstate->side[THEIRS], fee_msat);
}
bool force_fee(struct channel_state *cstate, uint64_t fee)
{
/* Beware overflow! */
if (fee > 0xFFFFFFFFFFFFFFFFULL / 1000)
return false;
recalculate_fees(&cstate->side[OURS], &cstate->side[THEIRS], fee * 1000);
return cstate->side[OURS].fee_msat + cstate->side[THEIRS].fee_msat == fee * 1000;
}
/* Add a HTLC to @creator if it can afford it. */
bool cstate_add_htlc(struct channel_state *cstate, const struct htlc *htlc)
{
size_t nondust;
struct channel_oneside *creator, *recipient;
creator = &cstate->side[htlc_channel_side(htlc)];
recipient = &cstate->side[!htlc_channel_side(htlc)];
/* Remember to count the new one in total txsize if not dust! */
nondust = cstate->num_nondust;
if (!is_dust(htlc->msatoshis / 1000))
nondust++;
if (!change_funding(cstate->anchor, cstate->fee_rate,
htlc->msatoshis, creator, recipient, nondust))
return false;
cstate->num_nondust = nondust;
creator->num_htlcs++;
return true;
}
/* Remove htlc from creator, credit it to beneficiary. */
static void remove_htlc(struct channel_state *cstate,
enum channel_side creator,
enum channel_side beneficiary,
const struct htlc *htlc)
{
size_t nondust;
/* Remember to remove this one in total txsize if not dust! */
nondust = cstate->num_nondust;
if (!is_dust(htlc->msatoshis / 1000)) {
assert(nondust > 0);
nondust--;
}
/* Can't fail since msatoshis is positive. */
if (!change_funding(cstate->anchor, cstate->fee_rate,
-(int64_t)htlc->msatoshis,
&cstate->side[beneficiary],
&cstate->side[!beneficiary], nondust))
abort();
/* Actually remove the HTLC. */
assert(cstate->side[creator].num_htlcs > 0);
cstate->side[creator].num_htlcs--;
cstate->num_nondust = nondust;
}
void cstate_fail_htlc(struct channel_state *cstate, const struct htlc *htlc)
{
remove_htlc(cstate, htlc_channel_side(htlc), htlc_channel_side(htlc),
htlc);
}
void cstate_fulfill_htlc(struct channel_state *cstate, const struct htlc *htlc)
{
remove_htlc(cstate, htlc_channel_side(htlc), !htlc_channel_side(htlc),
htlc);
}
struct channel_state *copy_cstate(const tal_t *ctx,
const struct channel_state *cstate)
{
return tal_dup(ctx, struct channel_state, cstate);
}