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pytest: don't wait for sendrawtx, wait for expected tx. 

In particular, test_no_fee_estimate was flaky due to seeing the funding
tx being sent.

Signed-off-by: Rusty Russell <rusty@rustcorp.com.au>
This commit is contained in:
Rusty Russell 2018-09-19 13:36:07 +09:30 committed by Christian Decker
parent 7744c41521
commit 252bbe1d2d
4 changed files with 24 additions and 20 deletions
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20
tests/test_closing.py
View File

@ -475,7 +475,7 @@ def test_onchain_unwatch(node_factory, bitcoind):
l1.rpc.dev_fail(l2.info['id'])
l1.daemon.wait_for_log('Failing due to dev-fail command')
l1.daemon.wait_for_log('sendrawtx exit 0')
l1.wait_for_channel_onchain(l2.info['id'])
l1.bitcoin.generate_block(1)
l1.daemon.wait_for_log(' to ONCHAIN')
@ -594,7 +594,7 @@ def test_onchain_dust_out(node_factory, bitcoind, executor):
# l1 will drop to chain.
l1.daemon.wait_for_log('permfail')
l1.daemon.wait_for_log('sendrawtx exit 0')
l1.wait_for_channel_onchain(l2.info['id'])
l1.bitcoin.generate_block(1)
l1.daemon.wait_for_log(' to ONCHAIN')
l2.daemon.wait_for_log(' to ONCHAIN')
@ -662,7 +662,7 @@ def test_onchain_timeout(node_factory, bitcoind, executor):
# l1 will drop to chain.
l1.daemon.wait_for_log('permfail')
l1.daemon.wait_for_log('sendrawtx exit 0')
l1.wait_for_channel_onchain(l2.info['id'])
l1.bitcoin.generate_block(1)
l1.daemon.wait_for_log(' to ONCHAIN')
l2.daemon.wait_for_log(' to ONCHAIN')
@ -814,7 +814,7 @@ def test_onchain_feechange(node_factory, bitcoind, executor):
# l2 will drop to chain.
l2.daemon.wait_for_log('permfail')
l2.daemon.wait_for_log('sendrawtx exit 0')
l2.wait_for_channel_onchain(l1.info['id'])
bitcoind.generate_block(1)
l1.daemon.wait_for_log(' to ONCHAIN')
l2.daemon.wait_for_log(' to ONCHAIN')
@ -890,7 +890,7 @@ def test_onchain_all_dust(node_factory, bitcoind, executor):
# l2 will drop to chain.
l2.daemon.wait_for_log('permfail')
l2.daemon.wait_for_log('sendrawtx exit 0')
l2.wait_for_channel_onchain(l1.info['id'])
# Make l1's fees really high (and wait for it to exceed 50000)
l1.set_feerates((100000, 100000, 100000))
@ -944,7 +944,7 @@ def test_onchain_different_fees(node_factory, bitcoind, executor):
# Drop to chain
l1.rpc.dev_fail(l2.info['id'])
l1.daemon.wait_for_log('sendrawtx exit 0')
l1.wait_for_channel_onchain(l2.info['id'])
bitcoind.generate_block(1)
l1.daemon.wait_for_log(' to ONCHAIN')
@ -999,7 +999,7 @@ def test_permfail_new_commit(node_factory, bitcoind, executor):
t = executor.submit(l1.pay, l2, 200000000)
l2.daemon.wait_for_log('dev_disconnect permfail')
l2.daemon.wait_for_log('sendrawtx exit 0')
l2.wait_for_channel_onchain(l1.info['id'])
bitcoind.generate_block(1)
l1.daemon.wait_for_log('Their unilateral tx, new commit point')
l1.daemon.wait_for_log(' to ONCHAIN')
@ -1037,7 +1037,7 @@ def test_permfail_htlc_in(node_factory, bitcoind, executor):
t = executor.submit(l1.pay, l2, 200000000)
l2.daemon.wait_for_log('dev_disconnect permfail')
l2.daemon.wait_for_log('sendrawtx exit 0')
l2.wait_for_channel_onchain(l1.info['id'])
bitcoind.generate_block(1)
l1.daemon.wait_for_log('Their unilateral tx, old commit point')
l1.daemon.wait_for_log(' to ONCHAIN')
@ -1082,7 +1082,7 @@ def test_permfail_htlc_out(node_factory, bitcoind, executor):
t = executor.submit(l2.pay, l1, 200000000)
l2.daemon.wait_for_log('dev_disconnect permfail')
l2.daemon.wait_for_log('sendrawtx exit 0')
l2.wait_for_channel_onchain(l1.info['id'])
bitcoind.generate_block(1)
l1.daemon.wait_for_log('Their unilateral tx, old commit point')
l1.daemon.wait_for_log(' to ONCHAIN')
@ -1144,7 +1144,7 @@ def test_permfail(node_factory, bitcoind):
# We fail l2, so l1 will reconnect to it.
l2.rpc.dev_fail(l1.info['id'])
l2.daemon.wait_for_log('Failing due to dev-fail command')
l2.daemon.wait_for_log('sendrawtx exit 0')
l2.wait_for_channel_onchain(l1.info['id'])
assert l1.bitcoin.rpc.getmempoolinfo()['size'] == 1

18
tests/test_connection.py
View File

@ -783,7 +783,7 @@ def test_channel_persistence(node_factory, bitcoind, executor):
# Now make sure l1 is watching for unilateral closes
l2.rpc.dev_fail(l1.info['id'])
l2.daemon.wait_for_log('Failing due to dev-fail command')
l2.daemon.wait_for_log('sendrawtx exit 0')
l2.wait_for_channel_onchain(l1.info['id'])
bitcoind.generate_block(1)
# L1 must notice.
@ -836,8 +836,8 @@ def test_update_fee(node_factory, bitcoind):
l2.daemon.wait_for_log(' to CLOSINGD_COMPLETE')
# And should put closing into mempool.
l1.daemon.wait_for_log('sendrawtx exit 0')
l2.daemon.wait_for_log('sendrawtx exit 0')
l1.wait_for_channel_onchain(l2.info['id'])
l2.wait_for_channel_onchain(l1.info['id'])
bitcoind.generate_block(1)
l1.daemon.wait_for_log(' to ONCHAIN')
@ -925,8 +925,8 @@ def test_update_fee_reconnect(node_factory, bitcoind):
l1.rpc.close(chan)
# And should put closing into mempool.
l1.daemon.wait_for_log('sendrawtx exit 0')
l2.daemon.wait_for_log('sendrawtx exit 0')
l1.wait_for_channel_onchain(l2.info['id'])
l2.wait_for_channel_onchain(l1.info['id'])
bitcoind.generate_block(1)
l1.daemon.wait_for_log(' to ONCHAIN')
@ -1150,7 +1150,7 @@ def test_no_fee_estimate(node_factory, bitcoind, executor):
l1.daemon.wait_for_log('sendrawtx exit 0')
l1.rpc.dev_fail(l2.info['id'])
l1.daemon.wait_for_log('Failing due to dev-fail command')
l1.daemon.wait_for_log('sendrawtx exit 0')
l1.wait_for_channel_onchain(l2.info['id'])
bitcoind.generate_block(6)
wait_for(lambda: only_one(l1.rpc.getpeer(l2.info['id'])['channels'])['state'] == 'ONCHAIN')
wait_for(lambda: only_one(l2.rpc.getpeer(l1.info['id'])['channels'])['state'] == 'ONCHAIN')
@ -1172,9 +1172,9 @@ def test_no_fee_estimate(node_factory, bitcoind, executor):
l2.pay(l1, 10**9 // 2)
l1.rpc.dev_fail(l2.info['id'])
l1.daemon.wait_for_log('Failing due to dev-fail command')
l1.daemon.wait_for_log('sendrawtx exit 0')
l1.wait_for_channel_onchain(l2.info['id'])
bitcoind.generate_block(5)
l1.daemon.wait_for_log('sendrawtx exit 0')
wait_for(lambda: len(bitcoind.rpc.getrawmempool()) > 0)
bitcoind.generate_block(100)
# Start estimatesmartfee.
@ -1280,7 +1280,7 @@ def test_dataloss_protection(node_factory, bitcoind):
l2.daemon.wait_for_log("Peer permanent failure in CHANNELD_NORMAL: Awaiting unilateral close")
# l1 should drop to chain.
l1.daemon.wait_for_log('sendrawtx exit 0')
l1.wait_for_channel_onchain(l2.info['id'])
# l2 must NOT drop to chain.
l2.daemon.wait_for_log("Cannot broadcast our commitment tx: they have a future one")

2
tests/test_misc.py
View File

@ -182,7 +182,7 @@ def test_htlc_sig_persistence(node_factory, executor):
# This should reload the htlc_sig
l2.rpc.dev_fail(l1.info['id'])
# Make sure it broadcasts to chain.
l2.daemon.wait_for_log('sendrawtx exit 0')
l2.wait_for_channel_onchain(l1.info['id'])
l2.stop()
l1.bitcoin.rpc.generate(1)
l1.start()

4
tests/utils.py
View File

@ -560,6 +560,10 @@ class LightningNode(object):
active = [(c['short_channel_id'], c['flags']) for c in channels if c['active']]
return (chanid, 0) in active and (chanid, 1) in active
def wait_for_channel_onchain(self, peerid):
txid = only_one(only_one(self.rpc.listpeers(peerid)['peers'])['channels'])['scratch_txid']
wait_for(lambda: txid in self.bitcoin.rpc.getrawmempool())
def wait_channel_active(self, chanid):
wait_for(lambda: self.is_channel_active(chanid), interval=1)