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pytest: Test `close` to the specified destination

This commit is contained in:
trueptolemy 2019-09-29 23:41:50 +08:00 committed by neil saitug
parent 019c052123
commit 63af8632b7
2 changed files with 67 additions and 0 deletions
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3
contrib/pylightning/lightning/lightning.py
View File

@ -342,6 +342,9 @@ class LightningRpc(UnixDomainSocketRpc):
if len(args) >= 1:
if isinstance(args[0], bool):
return self._deprecated_close(peer_id, *args, **kwargs)
if len(args) == 2:
if args[0] is None and isinstance(args[1], int):
return self._deprecated_close(peer_id, *args, **kwargs)
def _close(peer_id, unilateraltimeout=None, destination=None):
payload = {

64
tests/test_closing.py
View File

@ -297,6 +297,70 @@ def test_closing_negotiation_reconnect(node_factory, bitcoind):
assert bitcoind.rpc.getmempoolinfo()['size'] == 1
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_closing_specified_destination(node_factory, bitcoind):
l1, l2, l3, l4 = node_factory.get_nodes(4)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.rpc.connect(l3.info['id'], 'localhost', l3.port)
l1.rpc.connect(l4.info['id'], 'localhost', l4.port)
chan12 = l1.fund_channel(l2, 10**6)
chan13 = l1.fund_channel(l3, 10**6)
chan14 = l1.fund_channel(l4, 10**6)
l1.pay(l2, 100000000)
l1.pay(l3, 100000000)
l1.pay(l4, 100000000)
bitcoind.generate_block(5)
addr = 'bcrt1qeyyk6sl5pr49ycpqyckvmttus5ttj25pd0zpvg'
l1.rpc.close(chan12, None, addr)
l1.rpc.call('close', {'id': chan13, 'destination': addr})
l1.rpc.call('close', [chan14, None, addr])
l1.daemon.wait_for_logs([' to CLOSINGD_SIGEXCHANGE'] * 3)
# Both nodes should have disabled the channel in their view
wait_for(lambda: len(l1.getactivechannels()) == 0)
assert bitcoind.rpc.getmempoolinfo()['size'] == 3
# Now grab the close transaction
closetxid = bitcoind.rpc.getrawmempool(False)
assert len(closetxid) == 3
idindex = {}
for n in [l2, l3, l4]:
billboard = only_one(l1.rpc.listpeers(n.info['id'])['peers'][0]['channels'])['status']
idindex[n] = [i for i in range(3) if billboard == [
'CLOSINGD_SIGEXCHANGE:We agreed on a closing fee of 5430 satoshi for tx:{}'.format(closetxid[i]),
]][0]
assert idindex[n] in range(3)
bitcoind.generate_block(1)
sync_blockheight(bitcoind, [l1, l2, l3, l4])
# l1 can't spent the output to addr.
assert not l1.daemon.is_in_log(r'Owning output.* \(SEGWIT\).* txid %s.* CONFIRMED' % closetxid[0])
assert not l1.daemon.is_in_log(r'Owning output.* \(SEGWIT\).* txid %s.* CONFIRMED' % closetxid[1])
assert not l1.daemon.is_in_log(r'Owning output.* \(SEGWIT\).* txid %s.* CONFIRMED' % closetxid[2])
# Check the txid has at least 1 confirmation
l2.daemon.wait_for_log(r'Owning output.* \(SEGWIT\).* txid %s.* CONFIRMED' % closetxid[idindex[l2]])
l3.daemon.wait_for_log(r'Owning output.* \(SEGWIT\).* txid %s.* CONFIRMED' % closetxid[idindex[l3]])
l4.daemon.wait_for_log(r'Owning output.* \(SEGWIT\).* txid %s.* CONFIRMED' % closetxid[idindex[l4]])
for n in [l2, l3, l4]:
# Make sure both nodes have grabbed their close tx funds
outputs = n.rpc.listfunds()['outputs']
assert closetxid[idindex[n]] in set([o['txid'] for o in outputs])
output_num2 = [o for o in outputs if o['txid'] == closetxid[idindex[n]]][0]['output']
output_num1 = 0 if output_num2 == 1 else 1
# Check the another address is addr
assert addr == bitcoind.rpc.gettxout(closetxid[idindex[n]], output_num1)['scriptPubKey']['addresses'][0]
assert 1 == bitcoind.rpc.gettxout(closetxid[idindex[n]], output_num1)['confirmations']
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_penalty_inhtlc(node_factory, bitcoind, executor, chainparams):
"""Test penalty transaction with an incoming HTLC"""