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pytest: force anchor tests to use more than one UTXO. 

They fail now, since one UTXO is not enough.

Signed-off-by: Rusty Russell <rusty@rustcorp.com.au>
This commit is contained in:
Rusty Russell 2023-10-30 15:48:59 +10:30
parent 1d677bcba7
commit b901f885e0
1 changed files with 38 additions and 3 deletions
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41
tests/test_closing.py
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@ -3703,17 +3703,34 @@ def test_onchain_rexmit_tx(node_factory, bitcoind):
wait_for(lambda: len(bitcoind.rpc.getrawmempool()) == 1)
@pytest.mark.xfail(strict=True)
@unittest.skipIf(TEST_NETWORK != 'regtest', 'elementsd anchors unsupported')
def test_closing_anchorspend_htlc_tx_rbf(node_factory, bitcoind):
# We want an outstanding HTLC for l1, so it uses anchor to push.
# Set feerates to lowball for now.
l1, l2 = node_factory.line_graph(2, opts=[{'feerates': (1000,) * 4,
'experimental-anchors': None},
'experimental-anchors': None,
'min-emergency-msat': 546000},
{'feerates': (1000,) * 4,
'experimental-anchors': None,
'disconnect': ['-WIRE_UPDATE_FAIL_HTLC']}])
assert 'anchors_zero_fee_htlc_tx/even' in only_one(l1.rpc.listpeerchannels()['channels'])['channel_type']['names']
# We reduce l1's UTXOs so it's forced to use more than one UTXO to push.
fundsats = int(only_one(l1.rpc.listfunds()['outputs'])['amount_msat'].to_satoshi())
psbt = l1.rpc.fundpsbt("all", "1000perkw", 1000)['psbt']
# Pay 5k sats in fees, send most to l2
psbt = l1.rpc.addpsbtoutput(fundsats - 20000 - 5000, psbt, destination=l2.rpc.newaddr()['bech32'])['psbt']
# 10x2000 sat outputs for l1 to use.
for i in range(10):
psbt = l1.rpc.addpsbtoutput(2000, psbt)['psbt']
l1.rpc.sendpsbt(l1.rpc.signpsbt(psbt)['signed_psbt'])
bitcoind.generate_block(1, wait_for_mempool=1)
sync_blockheight(bitcoind, [l1])
# Make sure all amounts are below 2000 sats!
assert [x for x in l1.rpc.listfunds()['outputs'] if x['amount_msat'] > 2000_000] == []
inv = l2.rpc.invoice(123000, 'label', 'description')
l2.rpc.delinvoice('label', 'unpaid')
@ -3732,7 +3749,7 @@ def test_closing_anchorspend_htlc_tx_rbf(node_factory, bitcoind):
l1.set_feerates((2000, 2000, 2000, 2000))
bitcoind.generate_block(14)
l1.daemon.wait_for_log('Peer permanent failure in CHANNELD_NORMAL: Offered HTLC 0 SENT_ADD_ACK_REVOCATION cltv 116 hit deadline')
l1.daemon.wait_for_log('Peer permanent failure in CHANNELD_NORMAL: Offered HTLC 0 SENT_ADD_ACK_REVOCATION cltv 117 hit deadline')
l1.daemon.wait_for_log('Creating anchor spend for local commit tx')
wait_for(lambda: len(bitcoind.rpc.getrawmempool()) == 2)
@ -3882,15 +3899,33 @@ def test_closing_minfee(node_factory, bitcoind):
bitcoind.generate_block(1, wait_for_mempool=txid)
@pytest.mark.xfail(strict=True)
@unittest.skipIf(TEST_NETWORK != 'regtest', 'elementsd anchors not supportd')
def test_peer_anchor_push(node_factory, bitcoind, executor, chainparams):
"""Test that we use anchor on peer's commit to CPFP tx"""
l1, l2, l3 = node_factory.line_graph(3, opts=[{},
{'experimental-anchors': None},
{'experimental-anchors': None,
'min-emergency-msat': 546000},
{'experimental-anchors': None,
'disconnect': ['-WIRE_UPDATE_FULFILL_HTLC']}],
wait_for_announce=True)
# We splinter l2's funds so it's forced to use more than one UTXO to push.
fundsats = int(only_one(l2.rpc.listfunds()['outputs'])['amount_msat'].to_satoshi())
OUTPUT_SAT = 10000
NUM_OUTPUTS = 10
psbt = l2.rpc.fundpsbt("all", "1000perkw", 1000)['psbt']
# Pay 5k sats in fees.
psbt = l2.rpc.addpsbtoutput(fundsats - OUTPUT_SAT * NUM_OUTPUTS - 5000, psbt, destination=l3.rpc.newaddr()['bech32'])['psbt']
for _ in range(NUM_OUTPUTS):
psbt = l2.rpc.addpsbtoutput(OUTPUT_SAT, psbt)['psbt']
l2.rpc.sendpsbt(l2.rpc.signpsbt(psbt)['signed_psbt'])
bitcoind.generate_block(1, wait_for_mempool=1)
sync_blockheight(bitcoind, [l2])
# Make sure all amounts are below OUTPUT_SAT sats!
assert [x for x in l2.rpc.listfunds()['outputs'] if x['amount_msat'] > Millisatoshi(str(OUTPUT_SAT) + "sat")] == []
# Get HTLC stuck, so l2 has reason to push commitment tx.
amt = 100_000_000
sticky_inv = l3.rpc.invoice(amt, 'sticky', 'sticky')