from collections import namedtuple from fixtures import * # noqa: F401,F403 from lightning import RpcError from utils import DEVELOPER, only_one, wait_for, sync_blockheight, VALGRIND import os import pytest import time import random import shutil import unittest def test_connect(node_factory): l1, l2 = node_factory.line_graph(2, fundchannel=False) # These should be in openingd. assert l1.rpc.getpeer(l2.info['id'])['connected'] assert l2.rpc.getpeer(l1.info['id'])['connected'] assert len(l1.rpc.getpeer(l2.info['id'])['channels']) == 0 assert len(l2.rpc.getpeer(l1.info['id'])['channels']) == 0 # Reconnect should be a noop ret = l1.rpc.connect(l2.info['id'], 'localhost', port=l2.port) assert ret['id'] == l2.info['id'] ret = l2.rpc.connect(l1.info['id'], host='localhost', port=l1.port) assert ret['id'] == l1.info['id'] # Should still only have one peer! assert len(l1.rpc.listpeers()) == 1 assert len(l2.rpc.listpeers()) == 1 # Should get reasonable error if unknown addr for peer. with pytest.raises(RpcError, match=r'No address known'): l1.rpc.connect('032cf15d1ad9c4a08d26eab1918f732d8ef8fdc6abb9640bf3db174372c491304e') # Should get reasonable error if connection refuse. with pytest.raises(RpcError, match=r'Connection establishment: Connection refused'): l1.rpc.connect('032cf15d1ad9c4a08d26eab1918f732d8ef8fdc6abb9640bf3db174372c491304e', 'localhost', 1) # Should get reasonable error if wrong key for peer. with pytest.raises(RpcError, match=r'Cryptographic handshake: peer closed connection \(wrong key\?\)'): l1.rpc.connect('032cf15d1ad9c4a08d26eab1918f732d8ef8fdc6abb9640bf3db174372c491304e', 'localhost', l2.port) def test_connect_standard_addr(node_factory): """Test standard node@host:port address """ l1, l2, l3 = node_factory.get_nodes(3) # node@host ret = l1.rpc.connect("{}@{}".format(l2.info['id'], 'localhost'), port=l2.port) assert ret['id'] == l2.info['id'] # node@host:port ret = l1.rpc.connect("{}@localhost:{}".format(l3.info['id'], l3.port)) assert ret['id'] == l3.info['id'] # node@[ipv6]:port --- not supported by our CI # ret = l1.rpc.connect("{}@[::1]:{}".format(l3.info['id'], l3.port)) # assert ret['id'] == l3.info['id'] def test_reconnect_channel_peers(node_factory, executor): l1 = node_factory.get_node(may_reconnect=True) l2 = node_factory.get_node(may_reconnect=True) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.fund_channel(l2, 10**6) l2.restart() # Should reconnect. wait_for(lambda: only_one(l1.rpc.listpeers(l2.info['id'])['peers'])['connected']) wait_for(lambda: only_one(l2.rpc.listpeers(l1.info['id'])['peers'])['connected']) # Connect command should succeed. l1.rpc.connect(l2.info['id'], 'localhost', l2.port) # Stop l2 and wait for l1 to notice. l2.stop() wait_for(lambda: not only_one(l1.rpc.listpeers(l2.info['id'])['peers'])['connected']) # Now should fail. with pytest.raises(RpcError, match=r'Connection refused'): l1.rpc.connect(l2.info['id'], 'localhost', l2.port) # Wait for exponential backoff to give us a 2 second window. l1.daemon.wait_for_log('Will try reconnect in 2 seconds') # It should now succeed when it restarts. l2.start() # Multiples should be fine! fut1 = executor.submit(l1.rpc.connect, l2.info['id'], 'localhost', l2.port) fut2 = executor.submit(l1.rpc.connect, l2.info['id'], 'localhost', l2.port) fut3 = executor.submit(l1.rpc.connect, l2.info['id'], 'localhost', l2.port) fut1.result(10) fut2.result(10) fut3.result(10) def test_balance(node_factory): l1, l2 = node_factory.line_graph(2, fundchannel=True) p1 = only_one(l1.rpc.getpeer(peer_id=l2.info['id'], level='info')['channels']) p2 = only_one(l2.rpc.getpeer(l1.info['id'], 'info')['channels']) assert p1['msatoshi_to_us'] == 10**6 * 1000 assert p1['msatoshi_total'] == 10**6 * 1000 assert p2['msatoshi_to_us'] == 0 assert p2['msatoshi_total'] == 10**6 * 1000 def test_bad_opening(node_factory): # l1 asks for a too-long locktime l1 = node_factory.get_node(options={'watchtime-blocks': 100}) l2 = node_factory.get_node(options={'max-locktime-blocks': 99}) ret = l1.rpc.connect(l2.info['id'], 'localhost', l2.port) assert ret['id'] == l2.info['id'] l1.daemon.wait_for_log('openingd-.*: Handed peer, entering loop') l2.daemon.wait_for_log('openingd-.*: Handed peer, entering loop') l1.fundwallet(10**6 + 1000000) with pytest.raises(RpcError): l1.rpc.fundchannel(l2.info['id'], 10**6) l2.daemon.wait_for_log('to_self_delay 100 larger than 99') def test_second_channel(node_factory): l1 = node_factory.get_node() l2 = node_factory.get_node() l3 = node_factory.get_node() l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.rpc.connect(l3.info['id'], 'localhost', l3.port) l1.fund_channel(l2, 10**6) l1.fund_channel(l3, 10**6) @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_disconnect(node_factory): # These should all make us fail disconnects = ['-WIRE_INIT', '@WIRE_INIT', '+WIRE_INIT'] l1 = node_factory.get_node(disconnect=disconnects) l2 = node_factory.get_node() with pytest.raises(RpcError): l1.rpc.connect(l2.info['id'], 'localhost', l2.port) with pytest.raises(RpcError): l1.rpc.connect(l2.info['id'], 'localhost', l2.port) with pytest.raises(RpcError): l1.rpc.connect(l2.info['id'], 'localhost', l2.port) # Should have 3 connect fails. for d in disconnects: l1.daemon.wait_for_log('Failed connected out for {}' .format(l2.info['id'])) # Should still only have one peer! assert len(l1.rpc.listpeers()) == 1 assert len(l2.rpc.listpeers()) == 1 @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_disconnect_funder(node_factory): # Now error on funder side duringchannel open. disconnects = ['-WIRE_OPEN_CHANNEL', '@WIRE_OPEN_CHANNEL', '+WIRE_OPEN_CHANNEL', '-WIRE_FUNDING_CREATED', '@WIRE_FUNDING_CREATED'] l1 = node_factory.get_node(disconnect=disconnects) l2 = node_factory.get_node() l1.fundwallet(2000000) for d in disconnects: l1.rpc.connect(l2.info['id'], 'localhost', l2.port) with pytest.raises(RpcError): l1.rpc.fundchannel(l2.info['id'], 20000) assert l1.rpc.getpeer(l2.info['id']) is None # This one will succeed. l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.rpc.fundchannel(l2.info['id'], 20000) # Should still only have one peer! assert len(l1.rpc.listpeers()) == 1 assert len(l2.rpc.listpeers()) == 1 @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_disconnect_fundee(node_factory): # Now error on fundee side during channel open. disconnects = ['-WIRE_ACCEPT_CHANNEL', '@WIRE_ACCEPT_CHANNEL', '+WIRE_ACCEPT_CHANNEL'] l1 = node_factory.get_node() l2 = node_factory.get_node(disconnect=disconnects) l1.fundwallet(2000000) for d in disconnects: l1.rpc.connect(l2.info['id'], 'localhost', l2.port) with pytest.raises(RpcError): l1.rpc.fundchannel(l2.info['id'], 20000) assert l1.rpc.getpeer(l2.info['id']) is None # This one will succeed. l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.rpc.fundchannel(l2.info['id'], 20000) # Should still only have one peer! assert len(l1.rpc.listpeers()) == 1 assert len(l2.rpc.listpeers()) == 1 @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_disconnect_half_signed(node_factory): # Now, these are the corner cases. Fundee sends funding_signed, # but funder doesn't receive it. disconnects = ['@WIRE_FUNDING_SIGNED'] l1 = node_factory.get_node() l2 = node_factory.get_node(disconnect=disconnects) l1.fundwallet(2000000) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) with pytest.raises(RpcError): l1.rpc.fundchannel(l2.info['id'], 20000) # Fundee remembers, funder doesn't. assert l1.rpc.getpeer(l2.info['id']) is None assert l2.rpc.getpeer(l1.info['id'])['id'] == l1.info['id'] @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_reconnect_signed(node_factory): # This will fail *after* both sides consider channel opening. disconnects = ['+WIRE_FUNDING_SIGNED'] l1 = node_factory.get_node(may_reconnect=True) l2 = node_factory.get_node(disconnect=disconnects, may_reconnect=True) l1.fundwallet(2000000) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.rpc.fundchannel(l2.info['id'], 20000) # They haven't forgotten each other. assert l1.rpc.getpeer(l2.info['id'])['id'] == l2.info['id'] assert l2.rpc.getpeer(l1.info['id'])['id'] == l1.info['id'] # Technically, this is async to fundchannel (and could reconnect first) l1.daemon.wait_for_logs(['sendrawtx exit 0', 'Peer has reconnected, state CHANNELD_AWAITING_LOCKIN']) l1.bitcoin.generate_block(6) l1.daemon.wait_for_log(' to CHANNELD_NORMAL') l2.daemon.wait_for_log(' to CHANNELD_NORMAL') @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_reconnect_openingd(node_factory): # Openingd thinks we're still opening; funder reconnects.. disconnects = ['0WIRE_ACCEPT_CHANNEL'] l1 = node_factory.get_node(may_reconnect=True) l2 = node_factory.get_node(disconnect=disconnects, may_reconnect=True) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.fundwallet(2000000) # l2 closes on l1, l1 forgets. with pytest.raises(RpcError): l1.rpc.fundchannel(l2.info['id'], 20000) assert l1.rpc.getpeer(l2.info['id']) is None # Reconnect. l1.rpc.connect(l2.info['id'], 'localhost', l2.port) # We should get a message about reconnecting. l2.daemon.wait_for_log('Killing openingd: Reconnected') l2.daemon.wait_for_log('lightning_openingd.*Handed peer, entering loop') # Should work fine. l1.rpc.fundchannel(l2.info['id'], 20000) l1.daemon.wait_for_log('sendrawtx exit 0') # Just to be sure, second openingd hand over to channeld. l2.daemon.wait_for_log('lightning_openingd.*UPDATE WIRE_OPENING_FUNDEE') @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_reconnect_gossiping(node_factory): # connectd thinks we're still gossiping; peer reconnects. disconnects = ['0WIRE_PING'] l1 = node_factory.get_node(may_reconnect=True) l2 = node_factory.get_node(disconnect=disconnects, may_reconnect=True) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l2.rpc.ping(l1.info['id'], 1, 65532) wait_for(lambda: l1.rpc.listpeers(l2.info['id'])['peers'] == []) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l2.daemon.wait_for_log('processing now old peer gone') def test_connect_stresstest(node_factory, executor): # This test is unreliable, but it's better than nothing. l1 = node_factory.get_node(may_reconnect=True) l2 = node_factory.get_node(may_reconnect=True) l3 = node_factory.get_node(may_reconnect=True) # Hack l3 into a clone of l2, to stress reconnect code. l3.stop() shutil.copyfile(os.path.join(l2.daemon.lightning_dir, 'hsm_secret'), os.path.join(l3.daemon.lightning_dir, 'hsm_secret')) l3.start() l3.info = l3.rpc.getinfo() assert l3.info['id'] == l2.info['id'] # We fire off random connect/disconnect commands. actions = [ (l2.rpc.connect, l1.info['id'], 'localhost', l1.port), (l3.rpc.connect, l1.info['id'], 'localhost', l3.port), (l1.rpc.connect, l2.info['id'], 'localhost', l2.port), (l1.rpc.connect, l3.info['id'], 'localhost', l3.port), (l1.rpc.disconnect, l2.info['id']) ] args = [random.choice(actions) for _ in range(1000)] # We get them all to connect to each other. futs = [] for a in args: futs.append(executor.submit(*a)) # We don't actually care if they fail, since some will. successes = 0 failures = 0 for f in futs: if f.exception(): failures += 1 else: f.result() successes += 1 assert successes > failures @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_reconnect_normal(node_factory): # Should reconnect fine even if locked message gets lost. disconnects = ['-WIRE_FUNDING_LOCKED', '@WIRE_FUNDING_LOCKED', '+WIRE_FUNDING_LOCKED'] l1 = node_factory.get_node(disconnect=disconnects, may_reconnect=True) l2 = node_factory.get_node(may_reconnect=True) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.fund_channel(l2, 10**6) @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_reconnect_sender_add1(node_factory): # Fail after add is OK, will cause payment failure though. disconnects = ['-WIRE_UPDATE_ADD_HTLC-nocommit', '+WIRE_UPDATE_ADD_HTLC-nocommit', '@WIRE_UPDATE_ADD_HTLC-nocommit'] # Feerates identical so we don't get gratuitous commit to update them l1 = node_factory.get_node(disconnect=disconnects, may_reconnect=True, feerates=(7500, 7500, 7500)) l2 = node_factory.get_node(may_reconnect=True) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.fund_channel(l2, 10**6) amt = 200000000 rhash = l2.rpc.invoice(amt, 'test_reconnect_sender_add1', 'desc')['payment_hash'] assert only_one(l2.rpc.listinvoices('test_reconnect_sender_add1')['invoices'])['status'] == 'unpaid' route = [{'msatoshi': amt, 'id': l2.info['id'], 'delay': 5, 'channel': '1x1x1'}] for i in range(0, len(disconnects)): l1.rpc.sendpay(route, rhash) with pytest.raises(RpcError): l1.rpc.waitsendpay(rhash) # Wait for reconnection. l1.daemon.wait_for_log('Already have funding locked in') # This will send commit, so will reconnect as required. l1.rpc.sendpay(route, rhash) @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_reconnect_sender_add(node_factory): disconnects = ['-WIRE_COMMITMENT_SIGNED', '@WIRE_COMMITMENT_SIGNED', '+WIRE_COMMITMENT_SIGNED', '-WIRE_REVOKE_AND_ACK', '@WIRE_REVOKE_AND_ACK', '+WIRE_REVOKE_AND_ACK'] # Feerates identical so we don't get gratuitous commit to update them l1 = node_factory.get_node(disconnect=disconnects, may_reconnect=True, feerates=(7500, 7500, 7500)) l2 = node_factory.get_node(may_reconnect=True) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.fund_channel(l2, 10**6) amt = 200000000 rhash = l2.rpc.invoice(amt, 'testpayment', 'desc')['payment_hash'] assert only_one(l2.rpc.listinvoices('testpayment')['invoices'])['status'] == 'unpaid' route = [{'msatoshi': amt, 'id': l2.info['id'], 'delay': 5, 'channel': '1x1x1'}] # This will send commit, so will reconnect as required. l1.rpc.sendpay(route, rhash) # Should have printed this for every reconnect. for i in range(0, len(disconnects)): l1.daemon.wait_for_log('Already have funding locked in') @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_reconnect_receiver_add(node_factory): disconnects = ['-WIRE_COMMITMENT_SIGNED', '@WIRE_COMMITMENT_SIGNED', '+WIRE_COMMITMENT_SIGNED', '-WIRE_REVOKE_AND_ACK', '@WIRE_REVOKE_AND_ACK', '+WIRE_REVOKE_AND_ACK'] # Feerates identical so we don't get gratuitous commit to update them l1 = node_factory.get_node(may_reconnect=True, feerates=(7500, 7500, 7500)) l2 = node_factory.get_node(disconnect=disconnects, may_reconnect=True) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.fund_channel(l2, 10**6) amt = 200000000 rhash = l2.rpc.invoice(amt, 'testpayment2', 'desc')['payment_hash'] assert only_one(l2.rpc.listinvoices('testpayment2')['invoices'])['status'] == 'unpaid' route = [{'msatoshi': amt, 'id': l2.info['id'], 'delay': 5, 'channel': '1x1x1'}] l1.rpc.sendpay(route, rhash) for i in range(len(disconnects)): l1.daemon.wait_for_log('Already have funding locked in') assert only_one(l2.rpc.listinvoices('testpayment2')['invoices'])['status'] == 'paid' @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_reconnect_receiver_fulfill(node_factory): # Ordering matters: after +WIRE_UPDATE_FULFILL_HTLC, channeld # will continue and try to send WIRE_COMMITMENT_SIGNED: if # that's the next failure, it will do two in one run. disconnects = ['@WIRE_UPDATE_FULFILL_HTLC', '+WIRE_UPDATE_FULFILL_HTLC', '-WIRE_UPDATE_FULFILL_HTLC', '-WIRE_COMMITMENT_SIGNED', '@WIRE_COMMITMENT_SIGNED', '+WIRE_COMMITMENT_SIGNED', '-WIRE_REVOKE_AND_ACK', '@WIRE_REVOKE_AND_ACK', '+WIRE_REVOKE_AND_ACK'] l1 = node_factory.get_node(may_reconnect=True) l2 = node_factory.get_node(disconnect=disconnects, may_reconnect=True) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.fund_channel(l2, 10**6) amt = 200000000 rhash = l2.rpc.invoice(amt, 'testpayment2', 'desc')['payment_hash'] assert only_one(l2.rpc.listinvoices('testpayment2')['invoices'])['status'] == 'unpaid' route = [{'msatoshi': amt, 'id': l2.info['id'], 'delay': 5, 'channel': '1x1x1'}] l1.rpc.sendpay(route, rhash) for i in range(len(disconnects)): l1.daemon.wait_for_log('Already have funding locked in') assert only_one(l2.rpc.listinvoices('testpayment2')['invoices'])['status'] == 'paid' @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_shutdown_reconnect(node_factory): disconnects = ['-WIRE_SHUTDOWN', '@WIRE_SHUTDOWN', '+WIRE_SHUTDOWN'] l1 = node_factory.get_node(disconnect=disconnects, may_reconnect=True) l2 = node_factory.get_node(may_reconnect=True) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) chan = l1.fund_channel(l2, 10**6) l1.pay(l2, 200000000) assert l1.bitcoin.rpc.getmempoolinfo()['size'] == 0 # This should return with an error, then close. with pytest.raises(RpcError, match=r'Channel close negotiation not finished'): l1.rpc.close(chan, False, 0) l1.daemon.wait_for_log(' to CHANNELD_SHUTTING_DOWN') l2.daemon.wait_for_log(' to CHANNELD_SHUTTING_DOWN') l1.daemon.wait_for_log(' to CLOSINGD_SIGEXCHANGE') l2.daemon.wait_for_log(' to CLOSINGD_SIGEXCHANGE') # And should put closing into mempool (happens async, so # CLOSINGD_COMPLETE may come first). l1.daemon.wait_for_logs(['sendrawtx exit 0', ' to CLOSINGD_COMPLETE']) l2.daemon.wait_for_logs(['sendrawtx exit 0', ' to CLOSINGD_COMPLETE']) assert l1.bitcoin.rpc.getmempoolinfo()['size'] == 1 def test_shutdown_awaiting_lockin(node_factory, bitcoind): l1 = node_factory.get_node() l2 = node_factory.get_node(options={'funding-confirms': 3}) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.fundwallet(10**6 + 1000000) chanid = l1.rpc.fundchannel(l2.info['id'], 10**6)['channel_id'] # Technically, this is async to fundchannel. l1.daemon.wait_for_log('sendrawtx exit 0') bitcoind.generate_block(1) # This should return with an error, then close. with pytest.raises(RpcError, match=r'Channel close negotiation not finished'): l1.rpc.close(chanid, False, 0) l1.daemon.wait_for_log('CHANNELD_AWAITING_LOCKIN to CHANNELD_SHUTTING_DOWN') l2.daemon.wait_for_log('CHANNELD_AWAITING_LOCKIN to CHANNELD_SHUTTING_DOWN') l1.daemon.wait_for_log('CHANNELD_SHUTTING_DOWN to CLOSINGD_SIGEXCHANGE') l2.daemon.wait_for_log('CHANNELD_SHUTTING_DOWN to CLOSINGD_SIGEXCHANGE') # And should put closing into mempool (happens async, so # CLOSINGD_COMPLETE may come first). l1.daemon.wait_for_logs(['sendrawtx exit 0', ' to CLOSINGD_COMPLETE']) l2.daemon.wait_for_logs(['sendrawtx exit 0', ' to CLOSINGD_COMPLETE']) assert bitcoind.rpc.getmempoolinfo()['size'] == 1 bitcoind.generate_block(1) l1.daemon.wait_for_log(' to ONCHAIN') l2.daemon.wait_for_log(' to ONCHAIN') bitcoind.generate_block(100) wait_for(lambda: l1.rpc.listpeers()['peers'] == []) wait_for(lambda: l2.rpc.listpeers()['peers'] == []) def test_funding_change(node_factory, bitcoind): """Add some funds, fund a channel, and make sure we remember the change """ l1, l2 = node_factory.line_graph(2, fundchannel=False) l1.fundwallet(10000000) bitcoind.generate_block(1) sync_blockheight(bitcoind, [l1]) outputs = l1.db_query('SELECT value FROM outputs WHERE status=0;') assert only_one(outputs)['value'] == 10000000 l1.rpc.fundchannel(l2.info['id'], 1000000) outputs = {r['status']: r['value'] for r in l1.db_query( 'SELECT status, SUM(value) AS value FROM outputs GROUP BY status;')} # The 10m out is spent and we have a change output of 9m-fee assert outputs[0] > 8990000 assert outputs[2] == 10000000 def test_funding_all(node_factory, bitcoind): """Add some funds, fund a channel using all funds, make sure no funds remain """ l1, l2 = node_factory.line_graph(2, fundchannel=False) l1.fundwallet(0.1 * 10**8) bitcoind.generate_block(1) sync_blockheight(bitcoind, [l1]) outputs = l1.db_query('SELECT value FROM outputs WHERE status=0;') assert only_one(outputs)['value'] == 10000000 l1.rpc.fundchannel(l2.info['id'], "all") outputs = l1.db_query('SELECT value FROM outputs WHERE status=0;') assert len(outputs) == 0 def test_funding_all_too_much(node_factory): """Add more than max possible funds, fund a channel using all funds we can. """ l1, l2 = node_factory.line_graph(2, fundchannel=False) l1.fundwallet(2**24 + 10000) l1.rpc.fundchannel(l2.info['id'], "all") assert only_one(l1.rpc.listfunds()['outputs'])['status'] == 'unconfirmed' assert only_one(l1.rpc.listfunds()['channels'])['channel_total_sat'] == 2**24 - 1 def test_funding_fail(node_factory, bitcoind): """Add some funds, fund a channel without enough funds""" # Previous runs with same bitcoind can leave funds! max_locktime = 5 * 6 * 24 l1 = node_factory.get_node(random_hsm=True, options={'max-locktime-blocks': max_locktime}) l2 = node_factory.get_node(options={'watchtime-blocks': max_locktime + 1}) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) funds = 1000000 addr = l1.rpc.newaddr()['address'] l1.bitcoin.rpc.sendtoaddress(addr, funds / 10**8) bitcoind.generate_block(1) # Wait for it to arrive. wait_for(lambda: len(l1.rpc.listfunds()['outputs']) > 0) # Fail because l1 dislikes l2's huge locktime. with pytest.raises(RpcError, match=r'to_self_delay \d+ larger than \d+'): l1.rpc.fundchannel(l2.info['id'], int(funds / 10)) assert only_one(l1.rpc.listpeers()['peers'])['connected'] assert only_one(l2.rpc.listpeers()['peers'])['connected'] # Restart l2 without ridiculous locktime. del l2.daemon.opts['watchtime-blocks'] l2.restart() l1.rpc.connect(l2.info['id'], 'localhost', l2.port) # We don't have enough left to cover fees if we try to spend it all. with pytest.raises(RpcError, match=r'Cannot afford transaction'): l1.rpc.fundchannel(l2.info['id'], funds) # Should still be connected. assert only_one(l1.rpc.listpeers()['peers'])['connected'] l2.daemon.wait_for_log('lightning_openingd-.*: Handed peer, entering loop') assert only_one(l2.rpc.listpeers()['peers'])['connected'] # This works. l1.rpc.fundchannel(l2.info['id'], int(funds / 10)) def test_funding_toolarge(node_factory, bitcoind): """Try to create a giant channel""" l1 = node_factory.get_node() l2 = node_factory.get_node() l1.rpc.connect(l2.info['id'], 'localhost', l2.port) # Send funds. amount = 2**24 bitcoind.rpc.sendtoaddress(l1.rpc.newaddr()['address'], amount / 10**8 + 0.01) bitcoind.generate_block(1) # Wait for it to arrive. wait_for(lambda: len(l1.rpc.listfunds()['outputs']) > 0) # Fail to open (too large) with pytest.raises(RpcError, match=r'Amount exceeded 16777215'): l1.rpc.fundchannel(l2.info['id'], amount) # This should work. amount = amount - 1 l1.rpc.fundchannel(l2.info['id'], amount) def test_lockin_between_restart(node_factory, bitcoind): l1 = node_factory.get_node(may_reconnect=True) l2 = node_factory.get_node(options={'funding-confirms': 3}, may_reconnect=True) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.fundwallet(10**6 + 1000000) l1.rpc.fundchannel(l2.info['id'], 10**6)['tx'] # l1 goes down. l1.stop() # Now 120 blocks go by... bitcoind.generate_block(120) # Restart l1.start() # All should be good. l1.daemon.wait_for_log(' to CHANNELD_NORMAL') l2.daemon.wait_for_log(' to CHANNELD_NORMAL') def test_funding_while_offline(node_factory, bitcoind): l1 = node_factory.get_node() addr = l1.rpc.newaddr()['address'] sync_blockheight(bitcoind, [l1]) # l1 goes down. l1.stop() # We send funds bitcoind.rpc.sendtoaddress(addr, (10**6 + 1000000) / 10**8) # Now 120 blocks go by... bitcoind.generate_block(120) # Restart l1.start() sync_blockheight(bitcoind, [l1]) assert len(l1.rpc.listfunds()['outputs']) == 1 @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_channel_persistence(node_factory, bitcoind, executor): # Start two nodes and open a channel (to remember). l2 will # mysteriously die while committing the first HTLC so we can # check that HTLCs reloaded from the DB work. # Feerates identical so we don't get gratuitous commit to update them l1 = node_factory.get_node(may_reconnect=True, feerates=(7500, 7500, 7500)) l2 = node_factory.get_node(disconnect=['=WIRE_COMMITMENT_SIGNED-nocommit'], may_reconnect=True) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) # Neither node should have a channel open, they are just connected for n in (l1, l2): assert(n.db_query('SELECT COUNT(id) as count FROM channels;')[0]['count'] == 0) l1.fund_channel(l2, 100000) peers = l1.rpc.listpeers()['peers'] assert(only_one(peers[0]['channels'])['state'] == 'CHANNELD_NORMAL') # Both nodes should now have exactly one channel in the database for n in (l1, l2): assert(n.db_query('SELECT COUNT(id) as count FROM channels;')[0]['count'] == 1) # Fire off a sendpay request, it'll get interrupted by a restart executor.submit(l1.pay, l2, 10000) # Wait for it to be committed to, i.e., stored in the DB l1.daemon.wait_for_log('peer_in WIRE_COMMITMENT_SIGNED') # Stop l2, l1 will reattempt to connect print("Killing l2 in mid HTLC") l2.daemon.kill() # Clear the disconnect and timer stop so we can proceed normally del l2.daemon.opts['dev-disconnect'] # Wait for l1 to notice wait_for(lambda: 'connected' not in only_one(l1.rpc.listpeers()['peers'][0]['channels'])) # Now restart l2 and it should reload peers/channels from the DB l2.start() wait_for(lambda: len(l2.rpc.listpeers()['peers']) == 1) # Wait for the restored HTLC to finish wait_for(lambda: only_one(l1.rpc.listpeers()['peers'][0]['channels'])['msatoshi_to_us'] == 99990000) wait_for(lambda: len([p for p in l1.rpc.listpeers()['peers'] if p['connected']])) wait_for(lambda: len([p for p in l2.rpc.listpeers()['peers'] if p['connected']])) # Now make sure this is really functional by sending a payment l1.pay(l2, 10000) # L1 doesn't actually update msatoshi_to_us until it receives # revoke_and_ack from L2, which can take a little bit. wait_for(lambda: only_one(l1.rpc.listpeers()['peers'][0]['channels'])['msatoshi_to_us'] == 99980000) assert only_one(l2.rpc.listpeers()['peers'][0]['channels'])['msatoshi_to_us'] == 20000 # Finally restart l1, and make sure it remembers l1.restart() assert only_one(l1.rpc.listpeers()['peers'][0]['channels'])['msatoshi_to_us'] == 99980000 # Now make sure l1 is watching for unilateral closes l2.rpc.dev_fail(l1.info['id']) l2.daemon.wait_for_log('Failing due to dev-fail command') l2.wait_for_channel_onchain(l1.info['id']) bitcoind.generate_block(1) # L1 must notice. l1.daemon.wait_for_log(' to ONCHAIN') def test_private_channel(node_factory): l1, l2 = node_factory.line_graph(2, announce_channels=False, wait_for_announce=False) l3, l4 = node_factory.line_graph(2, announce_channels=True, wait_for_announce=True) assert l1.daemon.is_in_log('Will open private channel with node {}'.format(l2.info['id'])) assert not l2.daemon.is_in_log('Will open private channel with node {}'.format(l1.info['id'])) assert not l3.daemon.is_in_log('Will open private channel with node {}'.format(l4.info['id'])) l3.daemon.wait_for_log('Received node_announcement for node {}'.format(l4.info['id'])) l4.daemon.wait_for_log('Received node_announcement for node {}'.format(l3.info['id'])) assert not l1.daemon.is_in_log('Received node_announcement for node {}'.format(l2.info['id'])) assert not l2.daemon.is_in_log('Received node_announcement for node {}'.format(l1.info['id'])) # test for 'private' flag in rpc output assert only_one(only_one(l1.rpc.listpeers(l2.info['id'])['peers'])['channels'])['private'] # check non-private channel assert not only_one(only_one(l4.rpc.listpeers(l3.info['id'])['peers'])['channels'])['private'] @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1 for --dev-broadcast-interval") def test_channel_reenable(node_factory): l1, l2 = node_factory.line_graph(2, opts={'may_reconnect': True}, fundchannel=True, wait_for_announce=True) l1.daemon.wait_for_log('Received node_announcement for node {}'.format(l2.info['id'])) l2.daemon.wait_for_log('Received node_announcement for node {}'.format(l1.info['id'])) # Both directions should be active before the restart wait_for(lambda: [c['active'] for c in l1.rpc.listchannels()['channels']] == [True, True]) # Restart l2, will cause l1 to reconnect l2.stop() wait_for(lambda: [c['active'] for c in l1.rpc.listchannels()['channels']] == [False, False]) l2.start() # Updates may be suppressed if redundant; just test results. wait_for(lambda: [c['active'] for c in l1.rpc.listchannels()['channels']] == [True, True]) wait_for(lambda: [c['active'] for c in l2.rpc.listchannels()['channels']] == [True, True]) @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_update_fee(node_factory, bitcoind): l1, l2 = node_factory.line_graph(2, fundchannel=True) chanid = l1.get_channel_scid(l2) # Make l1 send out feechange. l1.set_feerates((14000, 7500, 3750)) l2.daemon.wait_for_log('peer updated fee to 14000') # Now make sure an HTLC works. # (First wait for route propagation.) l1.wait_channel_active(chanid) sync_blockheight(bitcoind, [l1, l2]) # Make payments. l1.pay(l2, 200000000) l2.pay(l1, 100000000) # Now shutdown cleanly. with pytest.raises(RpcError, match=r'Channel close negotiation not finished'): l1.rpc.close(chanid, False, 0) l1.daemon.wait_for_log(' to CLOSINGD_COMPLETE') l2.daemon.wait_for_log(' to CLOSINGD_COMPLETE') # And should put closing into mempool. l1.wait_for_channel_onchain(l2.info['id']) l2.wait_for_channel_onchain(l1.info['id']) bitcoind.generate_block(1) l1.daemon.wait_for_log(' to ONCHAIN') l2.daemon.wait_for_log(' to ONCHAIN') bitcoind.generate_block(99) l1.daemon.wait_for_log('onchaind complete, forgetting peer') l2.daemon.wait_for_log('onchaind complete, forgetting peer') @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_fee_limits(node_factory): # FIXME: Test case where opening denied. l1, l2 = node_factory.line_graph(2, opts={'dev-max-fee-multiplier': 5, 'may_reconnect': True}, fundchannel=True) # L1 asks for stupid low fee (will actually hit the floor of 253) l1.stop() l1.set_feerates((15, 15, 15), False) l1.start() l1.daemon.wait_for_log('Peer permanent failure in CHANNELD_NORMAL: lightning_channeld: received ERROR channel .*: update_fee 253 outside range 1875-75000') # Make sure the resolution of this one doesn't interfere with the next! # Note: may succeed, may fail with insufficient fee, depending on how # bitcoind feels! l1.daemon.wait_for_log('sendrawtx exit') # Restore to normal. l1.stop() l1.set_feerates((15000, 7500, 3750), False) l1.start() # Try with node which sets --ignore-fee-limits l3 = node_factory.get_node(options={'ignore-fee-limits': 'true'}, may_reconnect=True) l1.rpc.connect(l3.info['id'], 'localhost', l3.port) chan = l1.fund_channel(l3, 10**6) # Try stupid high fees l1.stop() l1.set_feerates((15000 * 10, 7500, 3750), False) l1.start() l3.daemon.wait_for_log('peer_in WIRE_UPDATE_FEE') l3.daemon.wait_for_log('peer_in WIRE_COMMITMENT_SIGNED') # We need to wait until both have committed and revoked the # old state, otherwise we'll still try to commit with the old # 15sat/byte fee l1.daemon.wait_for_log('peer_out WIRE_REVOKE_AND_ACK') # This should wait for close to complete l1.rpc.close(chan) @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_update_fee_reconnect(node_factory, bitcoind): # Disconnect after first commitsig. disconnects = ['+WIRE_COMMITMENT_SIGNED'] # Feerates identical so we don't get gratuitous commit to update them l1 = node_factory.get_node(disconnect=disconnects, may_reconnect=True, feerates=(15000, 15000, 3750)) # We match l2's later feerate, so we agree on same closing tx for simplicity. l2 = node_factory.get_node(may_reconnect=True, feerates=(14000, 14000, 3750)) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) chan = l1.fund_channel(l2, 10**6) # Make l1 send out feechange; triggers disconnect/reconnect. # (Note: < 10% change, so no smoothing here!) l1.set_feerates((14000, 14000, 3750)) l1.daemon.wait_for_log('Setting REMOTE feerate to 14000') l2.daemon.wait_for_log('Setting LOCAL feerate to 14000') l1.daemon.wait_for_log(r'dev_disconnect: \+WIRE_COMMITMENT_SIGNED') # Wait for reconnect.... l1.daemon.wait_for_log('Applying feerate 14000 to LOCAL') l1.pay(l2, 200000000) l2.pay(l1, 100000000) # They should both have gotten commits with correct feerate. assert l1.daemon.is_in_log('got commitsig [0-9]*: feerate 14000') assert l2.daemon.is_in_log('got commitsig [0-9]*: feerate 14000') # Now shutdown cleanly. l1.rpc.close(chan) # And should put closing into mempool. l1.wait_for_channel_onchain(l2.info['id']) l2.wait_for_channel_onchain(l1.info['id']) bitcoind.generate_block(1) l1.daemon.wait_for_log(' to ONCHAIN') l2.daemon.wait_for_log(' to ONCHAIN') bitcoind.generate_block(99) l1.daemon.wait_for_log('onchaind complete, forgetting peer') l2.daemon.wait_for_log('onchaind complete, forgetting peer') @unittest.skipIf(not DEVELOPER, "Too slow without --dev-bitcoind-poll") def test_multiple_channels(node_factory): l1 = node_factory.get_node() l2 = node_factory.get_node() for i in range(3): # FIXME: we shouldn't disconnect on close? ret = l1.rpc.connect(l2.info['id'], 'localhost', l2.port) assert ret['id'] == l2.info['id'] l1.daemon.wait_for_log('openingd-.*: Handed peer, entering loop') l2.daemon.wait_for_log('openingd-.*: Handed peer, entering loop') chan = l1.fund_channel(l2, 10**6) l1.rpc.close(chan) channels = only_one(l1.rpc.listpeers()['peers'])['channels'] assert len(channels) == 3 # Most in state ONCHAIN, last is CLOSINGD_COMPLETE for i in range(len(channels) - 1): assert channels[i]['state'] == 'ONCHAIN' assert channels[-1]['state'] == 'CLOSINGD_COMPLETE' @unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1") def test_forget_channel(node_factory): l1 = node_factory.get_node() l2 = node_factory.get_node() l1.fundwallet(10**6) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.rpc.fundchannel(l2.info['id'], 10**5) assert len(l1.rpc.listpeers()['peers']) == 1 # This should fail, the funding tx is in the mempool and may confirm with pytest.raises(RpcError, match=r'Cowardly refusing to forget channel'): l1.rpc.dev_forget_channel(l2.info['id']) assert len(l1.rpc.listpeers()['peers']) == 1 # Forcing should work l1.rpc.dev_forget_channel(l2.info['id'], True) assert len(l1.rpc.listpeers()['peers']) == 0 # And restarting should keep that peer forgotten l1.restart() assert len(l1.rpc.listpeers()['peers']) == 0 def test_peerinfo(node_factory, bitcoind): l1, l2 = node_factory.line_graph(2, fundchannel=False, opts={'may_reconnect': True}) lfeatures = '8a' # Gossiping but no node announcement yet assert l1.rpc.getpeer(l2.info['id'])['connected'] assert len(l1.rpc.getpeer(l2.info['id'])['channels']) == 0 assert l1.rpc.getpeer(l2.info['id'])['localfeatures'] == lfeatures # Fund a channel to force a node announcement chan = l1.fund_channel(l2, 10**6) # Now proceed to funding-depth and do a full gossip round bitcoind.generate_block(5) l1.daemon.wait_for_logs(['Received node_announcement for node ' + l2.info['id']]) l2.daemon.wait_for_logs(['Received node_announcement for node ' + l1.info['id']]) # Should have announced the same global features as told to peer. nodes1 = l1.rpc.listnodes(l2.info['id'])['nodes'] nodes2 = l2.rpc.listnodes(l2.info['id'])['nodes'] peer1 = l1.rpc.getpeer(l2.info['id']) peer2 = l2.rpc.getpeer(l1.info['id']) assert only_one(nodes1)['globalfeatures'] == peer1['globalfeatures'] assert only_one(nodes2)['globalfeatures'] == peer2['globalfeatures'] assert l1.rpc.getpeer(l2.info['id'])['localfeatures'] == lfeatures assert l2.rpc.getpeer(l1.info['id'])['localfeatures'] == lfeatures # If it reconnects after db load, it should know features. l1.restart() wait_for(lambda: l1.rpc.getpeer(l2.info['id'])['connected']) wait_for(lambda: l2.rpc.getpeer(l1.info['id'])['connected']) assert l1.rpc.getpeer(l2.info['id'])['localfeatures'] == lfeatures assert l2.rpc.getpeer(l1.info['id'])['localfeatures'] == lfeatures # Close the channel to forget the peer with pytest.raises(RpcError, match=r'Channel close negotiation not finished'): l1.rpc.close(chan, False, 0) wait_for(lambda: not only_one(l1.rpc.listpeers(l2.info['id'])['peers'])['connected']) wait_for(lambda: not only_one(l2.rpc.listpeers(l1.info['id'])['peers'])['connected']) bitcoind.generate_block(100) l1.daemon.wait_for_log('WIRE_ONCHAIN_ALL_IRREVOCABLY_RESOLVED') l2.daemon.wait_for_log('WIRE_ONCHAIN_ALL_IRREVOCABLY_RESOLVED') # The only channel was closed, everybody should have forgotten the nodes assert l1.rpc.listnodes()['nodes'] == [] assert l2.rpc.listnodes()['nodes'] == [] def test_disconnectpeer(node_factory, bitcoind): l1, l2, l3 = node_factory.get_nodes(3, opts={'may_reconnect': False}) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.rpc.connect(l3.info['id'], 'localhost', l3.port) # Gossiping assert l1.rpc.getpeer(l2.info['id'])['connected'] assert len(l1.rpc.getpeer(l2.info['id'])['channels']) == 0 assert l1.rpc.getpeer(l3.info['id'])['connected'] assert len(l1.rpc.getpeer(l3.info['id'])['channels']) == 0 wait_for(lambda: l2.rpc.getpeer(l1.info['id']) is not None) # Disconnect l2 from l1 l1.rpc.disconnect(l2.info['id']) # Make sure listpeers no longer returns the disconnected node assert l1.rpc.getpeer(l2.info['id']) is None wait_for(lambda: l2.rpc.getpeer(l1.info['id']) is None) # Make sure you cannot disconnect after disconnecting with pytest.raises(RpcError, match=r'Peer not connected'): l1.rpc.disconnect(l2.info['id']) with pytest.raises(RpcError, match=r'Peer not connected'): l2.rpc.disconnect(l1.info['id']) # Fund channel l1 -> l3 l1.fund_channel(l3, 10**6) bitcoind.generate_block(5) # disconnecting a non gossiping peer results in error with pytest.raises(RpcError, match=r'Peer is in state CHANNELD_NORMAL'): l1.rpc.disconnect(l3.info['id']) @unittest.skipIf(not DEVELOPER, "needs --dev-max-funding-unconfirmed-blocks") def test_fundee_forget_funding_tx_unconfirmed(node_factory, bitcoind): """Test that fundee will forget the channel if the funding tx has been unconfirmed for too long. """ # Keep this low (default is 2016), since everything # is much slower in VALGRIND mode and wait_for_log # could time out before lightningd processes all the # blocks. blocks = 200 # funder l1 = node_factory.get_node() # fundee l2 = node_factory.get_node(options={"dev-max-funding-unconfirmed-blocks": blocks}) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) # Give funder some funds. l1.fundwallet(10**7) # Let blocks settle. time.sleep(1) def mock_sendrawtransaction(r): return {'id': r['id'], 'error': {'code': 100, 'message': 'sendrawtransaction disabled'}} # Prevent funder from broadcasting funding tx (any tx really). l1.daemon.rpcproxy.mock_rpc('sendrawtransaction', mock_sendrawtransaction) # Fund the channel. # The process will complete, but funder will be unable # to broadcast and confirm funding tx. with pytest.raises(RpcError, match=r'sendrawtransaction disabled'): l1.rpc.fundchannel(l2.info['id'], 10**6) # Generate blocks until unconfirmed. bitcoind.generate_block(blocks) # fundee will forget channel! l2.daemon.wait_for_log('Forgetting channel: It has been {} blocks'.format(blocks)) # fundee will also forget and disconnect from peer. assert len(l2.rpc.listpeers(l1.info['id'])['peers']) == 0 @unittest.skipIf(not DEVELOPER, "needs dev_fail") def test_no_fee_estimate(node_factory, bitcoind, executor): l1 = node_factory.get_node(start=False) # Fail any fee estimation requests until we allow them further down l1.daemon.rpcproxy.mock_rpc('estimatesmartfee', { 'error': {"errors": ["Insufficient data or no feerate found"], "blocks": 0} }) l1.start() l2 = node_factory.get_node() l1.rpc.connect(l2.info['id'], 'localhost', l2.port) # Can't fund a channel. l1.fundwallet(10**7) with pytest.raises(RpcError, match=r'Cannot estimate fees'): l1.rpc.fundchannel(l2.info['id'], 10**6) # Can't withdraw either. with pytest.raises(RpcError, match=r'Cannot estimate fees'): l1.rpc.withdraw(l2.rpc.newaddr()['address'], 'all') # Can't use feerate names, either. with pytest.raises(RpcError, match=r'Cannot estimate fees'): l1.rpc.withdraw(l2.rpc.newaddr()['address'], 'all', 'urgent') l1.rpc.withdraw(l2.rpc.newaddr()['address'], 'all', 'normal') l1.rpc.withdraw(l2.rpc.newaddr()['address'], 'all', 'slow') with pytest.raises(RpcError, match=r'Cannot estimate fees'): l1.rpc.fundchannel(l2.info['id'], 10**6, 'urgent') l1.rpc.fundchannel(l2.info['id'], 10**6, 'normal') l1.rpc.fundchannel(l2.info['id'], 10**6, 'slow') # Can with manual feerate. l1.rpc.withdraw(l2.rpc.newaddr()['address'], 10000, '1500perkb') l1.rpc.fundchannel(l2.info['id'], 10**6, '2000perkw') # Make sure we clean up cahnnel for later attempt. l1.daemon.wait_for_log('sendrawtx exit 0') l1.rpc.dev_fail(l2.info['id']) l1.daemon.wait_for_log('Failing due to dev-fail command') l1.wait_for_channel_onchain(l2.info['id']) bitcoind.generate_block(6) wait_for(lambda: only_one(l1.rpc.getpeer(l2.info['id'])['channels'])['state'] == 'ONCHAIN') wait_for(lambda: only_one(l2.rpc.getpeer(l1.info['id'])['channels'])['state'] == 'ONCHAIN') # But can accept incoming connections. l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l2.fund_channel(l1, 10**6) # Can do HTLCs. l2.pay(l1, 10**5) # Can do mutual close. l1.rpc.close(l2.info['id']) bitcoind.generate_block(100) # Can do unilateral close. l2.rpc.connect(l1.info['id'], 'localhost', l1.port) l2.fund_channel(l1, 10**6) l2.pay(l1, 10**9 // 2) l1.rpc.dev_fail(l2.info['id']) l1.daemon.wait_for_log('Failing due to dev-fail command') l1.wait_for_channel_onchain(l2.info['id']) bitcoind.generate_block(5) wait_for(lambda: len(bitcoind.rpc.getrawmempool()) > 0) bitcoind.generate_block(100) # Start estimatesmartfee. l1.set_feerates((15000, 7500, 3750), True) # Can now fund a channel (as a test, use slow feerate). l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.rpc.fundchannel(l2.info['id'], 10**6, 'slow') # Can withdraw (use urgent feerate). l1.rpc.withdraw(l2.rpc.newaddr()['address'], 'all', 'urgent') @unittest.skipIf(not DEVELOPER, "needs --dev-disconnect") def test_funder_feerate_reconnect(node_factory, bitcoind): # l1 updates fees, then reconnect so l2 retransmits commitment_signed. disconnects = ['-WIRE_COMMITMENT_SIGNED'] l1 = node_factory.get_node(may_reconnect=True, feerates=(7500, 7500, 7500)) l2 = node_factory.get_node(disconnect=disconnects, may_reconnect=True) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.fund_channel(l2, 10**6) # create fee update, causing disconnect. l1.set_feerates((15000, 7500, 3750)) l2.daemon.wait_for_log(r'dev_disconnect: \-WIRE_COMMITMENT_SIGNED') # Wait until they reconnect. l1.daemon.wait_for_log('Peer transient failure in CHANNELD_NORMAL') wait_for(lambda: l1.rpc.getpeer(l2.info['id'])['connected']) # Should work normally. l1.pay(l2, 200000000) def test_funder_simple_reconnect(node_factory, bitcoind): """Sanity check that reconnection works with completely unused channels""" # Set fees even so it doesn't send any commitments. l1 = node_factory.get_node(may_reconnect=True, feerates=(7500, 7500, 7500)) l2 = node_factory.get_node(may_reconnect=True) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) l1.fund_channel(l2, 10**6) l1.rpc.disconnect(l2.info['id'], True) # Wait until they reconnect. wait_for(lambda: l1.rpc.getpeer(l2.info['id'])['connected']) # Should work normally. l1.pay(l2, 200000000) @unittest.skipIf(not DEVELOPER, "needs LIGHTNINGD_DEV_LOG_IO") def test_dataloss_protection(node_factory, bitcoind): l1 = node_factory.get_node(may_reconnect=True, log_all_io=True, feerates=(7500, 7500, 7500)) l2 = node_factory.get_node(may_reconnect=True, log_all_io=True, feerates=(7500, 7500, 7500)) l1.rpc.connect(l2.info['id'], 'localhost', l2.port) # l1 should send out WIRE_INIT (0010) l1.daemon.wait_for_log(r"\[OUT\] 0010" # gflen == 0 "0000" # lflen == 1 "0001" # Local features 1, 3 and 7 (0x8a). "8a") l1.fund_channel(l2, 10**6) l2.stop() # Save copy of the db. dbpath = os.path.join(l2.daemon.lightning_dir, "lightningd.sqlite3") orig_db = open(dbpath, "rb").read() l2.start() # l1 should have sent WIRE_CHANNEL_REESTABLISH with option_data_loss_protect. l1.daemon.wait_for_log(r"\[OUT\] 0088" # channel_id "[0-9a-f]{64}" # next_local_commitment_number "0000000000000001" # next_remote_revocation_number "0000000000000000" # your_last_per_commitment_secret (funding_depth may # trigger a fee-update and commit, hence this may not # be zero) "[0-9a-f]{64}" # my_current_per_commitment_point "0[23][0-9a-f]{64}") # After an htlc, we should get different results (two more commits) l1.pay(l2, 200000000) # Make sure both sides consider it completely settled (has received both # REVOKE_AND_ACK) l1.daemon.wait_for_logs([r"\[IN\] 0085"] * 2) l2.daemon.wait_for_logs([r"\[IN\] 0085"] * 2) l2.restart() # l1 should have sent WIRE_CHANNEL_REESTABLISH with option_data_loss_protect. l1.daemon.wait_for_log(r"\[OUT\] 0088" # channel_id "[0-9a-f]{64}" # next_local_commitment_number "000000000000000[1-9]" # next_remote_revocation_number "000000000000000[1-9]" # your_last_per_commitment_secret "[0-9a-f]{64}" # my_current_per_commitment_point "0[23][0-9a-f]{64}") # Now, move l2 back in time. l2.stop() # Overwrite with OLD db. open(dbpath, "wb").write(orig_db) l2.start() # l2 should freak out! l2.daemon.wait_for_log("Peer permanent failure in CHANNELD_NORMAL: Awaiting unilateral close") # l1 should drop to chain. l1.wait_for_channel_onchain(l2.info['id']) # l2 must NOT drop to chain. l2.daemon.wait_for_log("Cannot broadcast our commitment tx: they have a future one") assert not l2.daemon.is_in_log('sendrawtx exit 0') closetxid = only_one(bitcoind.rpc.getrawmempool(False)) # l2 should still recover something! bitcoind.generate_block(1) l2.daemon.wait_for_log("ERROR: Unknown commitment #[0-9], recovering our funds!") # Restarting l2, and it should remember from db. l2.restart() l2.daemon.wait_for_log("ERROR: Unknown commitment #[0-9], recovering our funds!") bitcoind.generate_block(100) l2.daemon.wait_for_log('WIRE_ONCHAIN_ALL_IRREVOCABLY_RESOLVED') # l2 should have it in wallet. assert (closetxid, "confirmed") in set([(o['txid'], o['status']) for o in l2.rpc.listfunds()['outputs']]) @unittest.skipIf(not DEVELOPER, "needs dev_disconnect") def test_restart_multi_htlc_rexmit(node_factory, bitcoind, executor): # l1 disables commit timer once we send first htlc, dies on commit disconnects = ['=WIRE_UPDATE_ADD_HTLC-nocommit', '-WIRE_COMMITMENT_SIGNED'] l1, l2 = node_factory.line_graph(2, opts=[{'disconnect': disconnects, 'may_reconnect': True}, {'may_reconnect': True}]) executor.submit(l1.pay, l2, 20000) executor.submit(l1.pay, l2, 30000) l1.daemon.wait_for_logs(['peer_out WIRE_UPDATE_ADD_HTLC'] * 2) l1.rpc.dev_reenable_commit(l2.info['id']) l1.daemon.wait_for_log('dev_disconnect: -WIRE_COMMITMENT_SIGNED') # This will make it reconnect l1.stop() # Clear the disconnect so we can proceed normally del l1.daemon.opts['dev-disconnect'] l1.start() # Payments will fail due to restart, but we can see results in listpayments. print(l1.rpc.listpayments()) wait_for(lambda: [p['status'] for p in l1.rpc.listpayments()['payments']] == ['complete', 'complete']) @unittest.skipIf(not DEVELOPER, "needs dev-disconnect") def test_fulfill_incoming_first(node_factory, bitcoind): """Test that we handle the case where we completely resolve incoming htlc before fulfilled outgoing htlc""" # We agree on fee change first, then add HTLC, then remove; stop after remove. disconnects = ['+WIRE_COMMITMENT_SIGNED*3'] # We manually reconnect l2 & l3, after 100 blocks; hence allowing manual # reconnect, but disabling auto connect, and massive cltv so 2/3 doesn't # time out. l1, l2, l3 = node_factory.line_graph(3, opts=[{}, {'may_reconnect': True, 'dev-no-reconnect': None}, {'may_reconnect': True, 'dev-no-reconnect': None, 'disconnect': disconnects, 'cltv-final': 200}], wait_for_announce=True) # This succeeds. l1.rpc.pay(l3.rpc.invoice(200000000, 'test_fulfill_incoming_first', 'desc')['bolt11']) # l1 can shutdown, fine. l1.rpc.close(l2.info['id']) l1.wait_for_channel_onchain(l2.info['id']) bitcoind.generate_block(100) l2.daemon.wait_for_log('onchaind complete, forgetting peer') # Now, l2 should restore from DB fine, even though outgoing HTLC no longer # has an incoming. l2.restart() # Manually reconnect l2->l3. l2.rpc.connect(l3.info['id'], 'localhost', l3.port) # Fulfill should be retransmitted OK (ignored result). l2.rpc.close(l3.info['id']) l2.wait_for_channel_onchain(l3.info['id']) bitcoind.generate_block(100) l2.daemon.wait_for_log('onchaind complete, forgetting peer') l3.daemon.wait_for_log('onchaind complete, forgetting peer') def test_restart_many_payments(node_factory): l1 = node_factory.get_node(may_reconnect=True) # On my laptop, these take 74 seconds and 44 seconds (with restart commented out) if VALGRIND: num = 2 else: num = 5 # Nodes with channels into the main node innodes = node_factory.get_nodes(num, opts={'may_reconnect': True}) inchans = [] for n in innodes: n.rpc.connect(l1.info['id'], 'localhost', l1.port) inchans.append(n.fund_channel(l1, 10**6, False)) # Nodes with channels out of the main node outnodes = node_factory.get_nodes(len(innodes), opts={'may_reconnect': True}) outchans = [] for n in outnodes: n.rpc.connect(l1.info['id'], 'localhost', l1.port) outchans.append(l1.fund_channel(n, 10**6, False)) # Now do all the waiting at once: if !DEVELOPER, this can be *very* slow! l1_logs = [] for i in range(len(innodes)): scid = inchans[i] l1_logs += [r'update for channel {}/0 now ACTIVE'.format(scid), r'update for channel {}/1 now ACTIVE'.format(scid), 'to CHANNELD_NORMAL'] innodes[i].daemon.wait_for_logs([r'update for channel {}/0 now ACTIVE' .format(scid), r'update for channel {}/1 now ACTIVE' .format(scid), 'to CHANNELD_NORMAL']) for i in range(len(outnodes)): scid = outchans[i] l1_logs += [r'update for channel {}/0 now ACTIVE'.format(scid), r'update for channel {}/1 now ACTIVE'.format(scid), 'to CHANNELD_NORMAL'] outnodes[i].daemon.wait_for_logs([r'update for channel {}/0 now ACTIVE' .format(scid), r'update for channel {}/1 now ACTIVE' .format(scid), 'to CHANNELD_NORMAL']) l1.daemon.wait_for_logs(l1_logs) # Manually create routes, get invoices Payment = namedtuple('Payment', ['innode', 'route', 'payment_hash']) to_pay = [] for i in range(len(innodes)): # This one will cause WIRE_INCORRECT_CLTV_EXPIRY from l1. route = [{'msatoshi': 100001001, 'id': l1.info['id'], 'delay': 10, 'channel': inchans[i]}, {'msatoshi': 100000000, 'id': outnodes[i].info['id'], 'delay': 5, 'channel': outchans[i]}] payment_hash = outnodes[i].rpc.invoice(100000000, "invoice", "invoice")['payment_hash'] to_pay.append(Payment(innodes[i], route, payment_hash)) # This one should be routed through to the outnode. route = [{'msatoshi': 100001001, 'id': l1.info['id'], 'delay': 11, 'channel': inchans[i]}, {'msatoshi': 100000000, 'id': outnodes[i].info['id'], 'delay': 5, 'channel': outchans[i]}] payment_hash = outnodes[i].rpc.invoice(100000000, "invoice2", "invoice2")['payment_hash'] to_pay.append(Payment(innodes[i], route, payment_hash)) # sendpay is async. for p in to_pay: p.innode.rpc.sendpay(p.route, p.payment_hash) # Now restart l1 while traffic is flowing... l1.restart() # Wait for them to finish. for n in innodes: wait_for(lambda: 'pending' not in [p['status'] for p in n.rpc.listpayments()['payments']])