88 lines
2.4 KiB
Python
88 lines
2.4 KiB
Python
from concurrent.futures import ThreadPoolExecutor
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from lightning import LightningRpc
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from test_lightningd import NodeFactory
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import logging
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import pytest
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import random
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import utils
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from concurrent import futures
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from time import time
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from tqdm import tqdm
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num_workers = 480
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num_payments = 10000
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@pytest.fixture
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def executor():
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ex = futures.ThreadPoolExecutor(max_workers=num_workers)
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yield ex
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ex.shutdown(wait=False)
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@pytest.fixture(scope="module")
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def bitcoind():
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bitcoind = utils.BitcoinD(rpcport=28332)
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bitcoind.start()
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info = bitcoind.rpc.getinfo()
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# Make sure we have segwit and some funds
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if info['blocks'] < 432:
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logging.debug("SegWit not active, generating some more blocks")
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bitcoind.generate_block(432 - info['blocks'])
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elif info['balance'] < 1:
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logging.debug("Insufficient balance, generating 1 block")
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bitcoind.generate_block(1)
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yield bitcoind
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try:
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bitcoind.rpc.stop()
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except:
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bitcoind.proc.kill()
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bitcoind.proc.wait()
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@pytest.fixture
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def node_factory(request, bitcoind, executor):
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nf = NodeFactory(request.node.name, bitcoind, executor)
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yield nf
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nf.killall()
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def test_single_hop(node_factory, executor):
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l1 = node_factory.get_node()
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l2 = node_factory.get_node()
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l1.rpc.connect(l2.rpc.getinfo()['id'], 'localhost:%d' % l2.rpc.getinfo()['port'])
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l1.openchannel(l2, 4000000)
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print("Collecting invoices")
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fs = []
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invoices = []
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for i in tqdm(range(num_payments)):
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invoices.append(l2.rpc.invoice(1000, 'invoice-%d' % (i), 'desc')['payment_hash'])
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route = l1.rpc.getroute(l2.rpc.getinfo()['id'], 1000, 1)['route']
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print("Sending payments")
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start_time = time()
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for i in invoices:
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fs.append(executor.submit(l1.rpc.sendpay, route, i))
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for f in tqdm(fs):
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f.result()
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diff = time() - start_time
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print("Done. %d payments performed in %f seconds (%f payments per second)" % (num_payments, diff, num_payments / diff))
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def test_single_payment(node_factory, benchmark):
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l1 = node_factory.get_node()
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l2 = node_factory.get_node()
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l1.rpc.connect(l2.rpc.getinfo()['id'], 'localhost:%d' % l2.rpc.getinfo()['port'])
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l1.openchannel(l2, 4000000)
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def do_pay(l1, l2):
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invoice = l2.rpc.invoice(1000, 'invoice-{}'.format(random.random()), 'desc')['bolt11']
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l1.rpc.pay(invoice)
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benchmark(do_pay, l1, l2)
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