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rgb-cln/tests/test_connection.py

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from collections import namedtuple
from fixtures import * # noqa: F401,F403
from flaky import flaky # noqa: F401
from lightning import RpcError
from utils import DEVELOPER, only_one, wait_for, sync_blockheight, VALGRIND, TIMEOUT, SLOW_MACHINE
from bitcoin.core import CMutableTransaction, CMutableTxOut
import binascii
import os
import pytest
import random
import re
import shutil
import time
import unittest
def test_connect(node_factory):
l1, l2 = node_factory.line_graph(2, fundchannel=False)
# These should be in openingd.
assert l1.rpc.getpeer(l2.info['id'])['connected']
assert l2.rpc.getpeer(l1.info['id'])['connected']
assert len(l1.rpc.getpeer(l2.info['id'])['channels']) == 0
assert len(l2.rpc.getpeer(l1.info['id'])['channels']) == 0
# Reconnect should be a noop
ret = l1.rpc.connect(l2.info['id'], 'localhost', port=l2.port)
assert ret['id'] == l2.info['id']
ret = l2.rpc.connect(l1.info['id'], host='localhost', port=l1.port)
assert ret['id'] == l1.info['id']
# Should still only have one peer!
assert len(l1.rpc.listpeers()) == 1
assert len(l2.rpc.listpeers()) == 1
# Should get reasonable error if unknown addr for peer.
with pytest.raises(RpcError, match=r'No address known'):
l1.rpc.connect('032cf15d1ad9c4a08d26eab1918f732d8ef8fdc6abb9640bf3db174372c491304e')
# Should get reasonable error if connection refuse.
with pytest.raises(RpcError, match=r'Connection establishment: Connection refused'):
l1.rpc.connect('032cf15d1ad9c4a08d26eab1918f732d8ef8fdc6abb9640bf3db174372c491304e', 'localhost', 1)
# Should get reasonable error if wrong key for peer.
with pytest.raises(RpcError, match=r'Cryptographic handshake: peer closed connection \(wrong key\?\)'):
l1.rpc.connect('032cf15d1ad9c4a08d26eab1918f732d8ef8fdc6abb9640bf3db174372c491304e', 'localhost', l2.port)
def test_connect_standard_addr(node_factory):
"""Test standard node@host:port address
"""
l1, l2, l3 = node_factory.get_nodes(3)
# node@host
ret = l1.rpc.connect("{}@{}".format(l2.info['id'], 'localhost'), port=l2.port)
assert ret['id'] == l2.info['id']
# node@host:port
ret = l1.rpc.connect("{}@localhost:{}".format(l3.info['id'], l3.port))
assert ret['id'] == l3.info['id']
# node@[ipv6]:port --- not supported by our CI
# ret = l1.rpc.connect("{}@[::1]:{}".format(l3.info['id'], l3.port))
# assert ret['id'] == l3.info['id']
def test_reconnect_channel_peers(node_factory, executor):
l1 = node_factory.get_node(may_reconnect=True)
l2 = node_factory.get_node(may_reconnect=True)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.fund_channel(l2, 10**6)
l2.restart()
# Should reconnect.
wait_for(lambda: only_one(l1.rpc.listpeers(l2.info['id'])['peers'])['connected'])
wait_for(lambda: only_one(l2.rpc.listpeers(l1.info['id'])['peers'])['connected'])
# Connect command should succeed.
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
# Stop l2 and wait for l1 to notice.
l2.stop()
wait_for(lambda: not only_one(l1.rpc.listpeers(l2.info['id'])['peers'])['connected'])
# Now should fail.
with pytest.raises(RpcError, match=r'Connection refused'):
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
# Wait for exponential backoff to give us a 2 second window.
l1.daemon.wait_for_log('Will try reconnect in 2 seconds')
# It should now succeed when it restarts.
l2.start()
# Multiples should be fine!
fut1 = executor.submit(l1.rpc.connect, l2.info['id'], 'localhost', l2.port)
fut2 = executor.submit(l1.rpc.connect, l2.info['id'], 'localhost', l2.port)
fut3 = executor.submit(l1.rpc.connect, l2.info['id'], 'localhost', l2.port)
fut1.result(10)
fut2.result(10)
fut3.result(10)
def test_balance(node_factory):
l1, l2 = node_factory.line_graph(2, fundchannel=True)
p1 = only_one(l1.rpc.getpeer(peer_id=l2.info['id'], level='info')['channels'])
p2 = only_one(l2.rpc.getpeer(l1.info['id'], 'info')['channels'])
assert p1['msatoshi_to_us'] == 10**6 * 1000
assert p1['msatoshi_total'] == 10**6 * 1000
assert p2['msatoshi_to_us'] == 0
assert p2['msatoshi_total'] == 10**6 * 1000
def test_bad_opening(node_factory):
# l1 asks for a too-long locktime
l1 = node_factory.get_node(options={'watchtime-blocks': 100})
l2 = node_factory.get_node(options={'max-locktime-blocks': 99})
ret = l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
assert ret['id'] == l2.info['id']
l1.daemon.wait_for_log('openingd-.*: Handed peer, entering loop')
l2.daemon.wait_for_log('openingd-.*: Handed peer, entering loop')
l1.fundwallet(10**6 + 1000000)
with pytest.raises(RpcError):
l1.rpc.fundchannel(l2.info['id'], 10**6)
l2.daemon.wait_for_log('to_self_delay 100 larger than 99')
@unittest.skipIf(not DEVELOPER, "gossip without DEVELOPER=1 is slow")
def test_opening_tiny_channel(node_factory):
# Test custom min-capacity-sat parameters
#
# o---> [l2] (1000) - old default (too little for reserves)
# /
# [l1]-----> [l3] (~6000) - technical minimal value that wont be rejected
# \
# o---> [l4] (~10000) - the current default
# \
# o-> [l5] (20000) - a node with a higher minimal value
#
# For each:
# 1. Try to establish channel 1sat smaller than min_capacity_sat
# 2. Try to establish channel exact min_capacity_sat
#
# BOLT2
# The receiving node MAY fail the channel if:
# - funding_satoshis is too small
# - it considers `feerate_per_kw` too small for timely processing or unreasonably large.
#
dustlimit = 546
reserves = 2 * dustlimit
min_commit_tx_fees = 5430
min_for_funder = min_commit_tx_fees + dustlimit + 1
l1_min_capacity = 1000 # 1k old default, too small but used at l1 to allow small incoming channels
l2_min_capacity = reserves # just enough to get past capacity filter
l3_min_capacity = min_for_funder # the absolute technical minimum
l4_min_capacity = 10000 # the current default
l5_min_capacity = 20000 # a server with more than default minimum
l1 = node_factory.get_node(options={'min-capacity-sat': l1_min_capacity})
l2 = node_factory.get_node(options={'min-capacity-sat': l2_min_capacity})
l3 = node_factory.get_node(options={'min-capacity-sat': l3_min_capacity})
l4 = node_factory.get_node(options={'min-capacity-sat': l4_min_capacity})
l5 = node_factory.get_node(options={'min-capacity-sat': l5_min_capacity})
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.rpc.connect(l3.info['id'], 'localhost', l3.port)
l1.rpc.connect(l4.info['id'], 'localhost', l4.port)
l1.rpc.connect(l5.info['id'], 'localhost', l5.port)
# Open channel with one less than reserves should be rejected at l2
with pytest.raises(RpcError, match=r'channel_reserve_satoshis .*sat and .*sat too large for funding .*sat'):
l1.fund_channel(l2, l2_min_capacity - 1)
# Open a channel with exactly the minimal amount for the fundee,
# This will raise an exception at l1, as the funder cannot afford fees for initial_commit_tx.
# Note: The old default of 1k sat is below the technical minimum when accounting for dust reserves and fees
# This is why this must fail, for this reason the default will be raised to 10k sat.
with pytest.raises(RpcError, match=r'Funder cannot afford fee on initial commitment transaction'):
l1.fund_channel(l2, l2_min_capacity)
# Open channel with one less than technical minimum should be rejected at l3
with pytest.raises(RpcError, match=r'channel capacity is .*sat, which is below .*sat'):
l1.fund_channel(l3, l3_min_capacity - 1)
# When amount technical minimum matches exactly, own initial_commit_tx fees can now be covered
l1.fund_channel(l3, l3_min_capacity)
# Open channel with one less than default 10k sats should be rejected at l4
with pytest.raises(RpcError, match=r'channel capacity is .*, which is below .*msat'):
l1.fund_channel(l4, l4_min_capacity - 1)
# This must be possible with enough capacity
l1.fund_channel(l4, l4_min_capacity)
# Open channel with less than minimum should be rejected at l5
with pytest.raises(RpcError, match=r'channel capacity is .*, which is below .*msat'):
l1.fund_channel(l5, l5_min_capacity - 1)
# bigger channels must not be affected
l1.fund_channel(l5, l5_min_capacity * 10)
def test_second_channel(node_factory):
l1 = node_factory.get_node()
l2 = node_factory.get_node()
l3 = node_factory.get_node()
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.rpc.connect(l3.info['id'], 'localhost', l3.port)
l1.fund_channel(l2, 10**6)
l1.fund_channel(l3, 10**6)
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_disconnect(node_factory):
# These should all make us fail
disconnects = ['-WIRE_INIT',
'@WIRE_INIT',
'+WIRE_INIT']
l1 = node_factory.get_node(disconnect=disconnects)
l2 = node_factory.get_node()
with pytest.raises(RpcError):
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
with pytest.raises(RpcError):
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
with pytest.raises(RpcError):
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
# Should have 3 connect fails.
for d in disconnects:
l1.daemon.wait_for_log('Failed connected out for {}'
.format(l2.info['id']))
# Should still only have one peer!
assert len(l1.rpc.listpeers()) == 1
assert len(l2.rpc.listpeers()) == 1
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_disconnect_funder(node_factory):
# Now error on funder side duringchannel open.
disconnects = ['-WIRE_OPEN_CHANNEL',
'@WIRE_OPEN_CHANNEL',
'+WIRE_OPEN_CHANNEL',
'-WIRE_FUNDING_CREATED',
'@WIRE_FUNDING_CREATED']
l1 = node_factory.get_node(disconnect=disconnects)
l2 = node_factory.get_node()
l1.fundwallet(2000000)
for d in disconnects:
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
with pytest.raises(RpcError):
l1.rpc.fundchannel(l2.info['id'], 20000)
assert l1.rpc.getpeer(l2.info['id']) is None
# This one will succeed.
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.rpc.fundchannel(l2.info['id'], 20000)
# Should still only have one peer!
assert len(l1.rpc.listpeers()) == 1
assert len(l2.rpc.listpeers()) == 1
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_disconnect_fundee(node_factory):
# Now error on fundee side during channel open.
disconnects = ['-WIRE_ACCEPT_CHANNEL',
'@WIRE_ACCEPT_CHANNEL',
'+WIRE_ACCEPT_CHANNEL']
l1 = node_factory.get_node()
l2 = node_factory.get_node(disconnect=disconnects)
l1.fundwallet(2000000)
for d in disconnects:
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
with pytest.raises(RpcError):
l1.rpc.fundchannel(l2.info['id'], 20000)
assert l1.rpc.getpeer(l2.info['id']) is None
# This one will succeed.
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.rpc.fundchannel(l2.info['id'], 20000)
# Should still only have one peer!
assert len(l1.rpc.listpeers()) == 1
assert len(l2.rpc.listpeers()) == 1
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_disconnect_half_signed(node_factory):
# Now, these are the corner cases. Fundee sends funding_signed,
# but funder doesn't receive it.
disconnects = ['@WIRE_FUNDING_SIGNED']
l1 = node_factory.get_node()
l2 = node_factory.get_node(disconnect=disconnects)
l1.fundwallet(2000000)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
with pytest.raises(RpcError):
l1.rpc.fundchannel(l2.info['id'], 20000)
# Fundee remembers, funder doesn't.
assert l1.rpc.getpeer(l2.info['id']) is None
assert l2.rpc.getpeer(l1.info['id'])['id'] == l1.info['id']
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_reconnect_signed(node_factory):
# This will fail *after* both sides consider channel opening.
disconnects = ['+WIRE_FUNDING_SIGNED']
l1 = node_factory.get_node(may_reconnect=True)
l2 = node_factory.get_node(disconnect=disconnects,
may_reconnect=True)
l1.fundwallet(2000000)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.rpc.fundchannel(l2.info['id'], 20000)
# They haven't forgotten each other.
assert l1.rpc.getpeer(l2.info['id'])['id'] == l2.info['id']
assert l2.rpc.getpeer(l1.info['id'])['id'] == l1.info['id']
# Technically, this is async to fundchannel (and could reconnect first)
l1.daemon.wait_for_logs(['sendrawtx exit 0',
'Peer has reconnected, state CHANNELD_AWAITING_LOCKIN'])
l1.bitcoin.generate_block(6)
l1.daemon.wait_for_log(' to CHANNELD_NORMAL')
l2.daemon.wait_for_log(' to CHANNELD_NORMAL')
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_reconnect_openingd(node_factory):
# Openingd thinks we're still opening; funder reconnects..
disconnects = ['0WIRE_ACCEPT_CHANNEL']
l1 = node_factory.get_node(may_reconnect=True)
l2 = node_factory.get_node(disconnect=disconnects,
may_reconnect=True)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.fundwallet(2000000)
# l2 closes on l1, l1 forgets.
with pytest.raises(RpcError):
l1.rpc.fundchannel(l2.info['id'], 20000)
assert l1.rpc.getpeer(l2.info['id']) is None
# Reconnect.
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
# We should get a message about reconnecting.
l2.daemon.wait_for_log('Killing openingd: Reconnected')
l2.daemon.wait_for_log('lightning_openingd.*Handed peer, entering loop')
# Should work fine.
l1.rpc.fundchannel(l2.info['id'], 20000)
l1.daemon.wait_for_log('sendrawtx exit 0')
l1.bitcoin.generate_block(3)
# Just to be sure, second openingd hand over to channeld. This log line is about channeld being started
l2.daemon.wait_for_log(r'lightning_channeld-[0-9a-f]{66} chan #[0-9]: pid [0-9]+, msgfd [0-9]+')
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_reconnect_gossiping(node_factory):
# connectd thinks we're still gossiping; peer reconnects.
disconnects = ['0WIRE_PING']
l1 = node_factory.get_node(may_reconnect=True)
l2 = node_factory.get_node(disconnect=disconnects,
may_reconnect=True)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
# Make sure l2 knows about l1
wait_for(lambda: l2.rpc.listpeers(l1.info['id'])['peers'] != [])
l2.rpc.ping(l1.info['id'], 1, 65532)
wait_for(lambda: l1.rpc.listpeers(l2.info['id'])['peers'] == [])
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l2.daemon.wait_for_log('processing now old peer gone')
def test_connect_stresstest(node_factory, executor):
# This test is unreliable, but it's better than nothing.
l1 = node_factory.get_node(may_reconnect=True)
l2 = node_factory.get_node(may_reconnect=True)
l3 = node_factory.get_node(may_reconnect=True)
# Hack l3 into a clone of l2, to stress reconnect code.
l3.stop()
shutil.copyfile(os.path.join(l2.daemon.lightning_dir, 'hsm_secret'),
os.path.join(l3.daemon.lightning_dir, 'hsm_secret'))
l3.start()
l3.info = l3.rpc.getinfo()
assert l3.info['id'] == l2.info['id']
# We fire off random connect/disconnect commands.
actions = [
(l2.rpc.connect, l1.info['id'], 'localhost', l1.port),
(l3.rpc.connect, l1.info['id'], 'localhost', l3.port),
(l1.rpc.connect, l2.info['id'], 'localhost', l2.port),
(l1.rpc.connect, l3.info['id'], 'localhost', l3.port),
(l1.rpc.disconnect, l2.info['id'])
]
args = [random.choice(actions) for _ in range(1000)]
# We get them all to connect to each other.
futs = []
for a in args:
futs.append(executor.submit(*a))
# We don't actually care if they fail, since some will.
successes = 0
failures = 0
for f in futs:
if f.exception():
failures += 1
else:
f.result()
successes += 1
assert successes > failures
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_reconnect_normal(node_factory):
# Should reconnect fine even if locked message gets lost.
disconnects = ['-WIRE_FUNDING_LOCKED',
'@WIRE_FUNDING_LOCKED',
'+WIRE_FUNDING_LOCKED']
l1 = node_factory.get_node(disconnect=disconnects,
may_reconnect=True)
l2 = node_factory.get_node(may_reconnect=True)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.fund_channel(l2, 10**6)
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_reconnect_sender_add1(node_factory):
# Fail after add is OK, will cause payment failure though.
disconnects = ['-WIRE_UPDATE_ADD_HTLC-nocommit',
'+WIRE_UPDATE_ADD_HTLC-nocommit',
'@WIRE_UPDATE_ADD_HTLC-nocommit']
# Feerates identical so we don't get gratuitous commit to update them
l1 = node_factory.get_node(disconnect=disconnects,
may_reconnect=True,
feerates=(7500, 7500, 7500))
l2 = node_factory.get_node(may_reconnect=True)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.fund_channel(l2, 10**6)
amt = 200000000
rhash = l2.rpc.invoice(amt, 'test_reconnect_sender_add1', 'desc')['payment_hash']
assert only_one(l2.rpc.listinvoices('test_reconnect_sender_add1')['invoices'])['status'] == 'unpaid'
route = [{'msatoshi': amt, 'id': l2.info['id'], 'delay': 5, 'channel': '1x1x1'}]
for i in range(0, len(disconnects)):
l1.rpc.sendpay(route, rhash)
with pytest.raises(RpcError):
l1.rpc.waitsendpay(rhash)
# Wait for reconnection.
l1.daemon.wait_for_log('Already have funding locked in')
# This will send commit, so will reconnect as required.
l1.rpc.sendpay(route, rhash)
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_reconnect_sender_add(node_factory):
disconnects = ['-WIRE_COMMITMENT_SIGNED',
'@WIRE_COMMITMENT_SIGNED',
'+WIRE_COMMITMENT_SIGNED',
'-WIRE_REVOKE_AND_ACK',
'@WIRE_REVOKE_AND_ACK',
'+WIRE_REVOKE_AND_ACK']
# Feerates identical so we don't get gratuitous commit to update them
l1 = node_factory.get_node(disconnect=disconnects,
may_reconnect=True,
feerates=(7500, 7500, 7500))
l2 = node_factory.get_node(may_reconnect=True)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.fund_channel(l2, 10**6)
amt = 200000000
rhash = l2.rpc.invoice(amt, 'testpayment', 'desc')['payment_hash']
assert only_one(l2.rpc.listinvoices('testpayment')['invoices'])['status'] == 'unpaid'
route = [{'msatoshi': amt, 'id': l2.info['id'], 'delay': 5, 'channel': '1x1x1'}]
# This will send commit, so will reconnect as required.
l1.rpc.sendpay(route, rhash)
# Should have printed this for every reconnect.
for i in range(0, len(disconnects)):
l1.daemon.wait_for_log('Already have funding locked in')
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_reconnect_receiver_add(node_factory):
disconnects = ['-WIRE_COMMITMENT_SIGNED',
'@WIRE_COMMITMENT_SIGNED',
'+WIRE_COMMITMENT_SIGNED',
'-WIRE_REVOKE_AND_ACK',
'@WIRE_REVOKE_AND_ACK',
'+WIRE_REVOKE_AND_ACK']
# Feerates identical so we don't get gratuitous commit to update them
l1 = node_factory.get_node(may_reconnect=True, feerates=(7500, 7500, 7500))
l2 = node_factory.get_node(disconnect=disconnects,
may_reconnect=True)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.fund_channel(l2, 10**6)
amt = 200000000
rhash = l2.rpc.invoice(amt, 'testpayment2', 'desc')['payment_hash']
assert only_one(l2.rpc.listinvoices('testpayment2')['invoices'])['status'] == 'unpaid'
route = [{'msatoshi': amt, 'id': l2.info['id'], 'delay': 5, 'channel': '1x1x1'}]
l1.rpc.sendpay(route, rhash)
for i in range(len(disconnects)):
l1.daemon.wait_for_log('Already have funding locked in')
assert only_one(l2.rpc.listinvoices('testpayment2')['invoices'])['status'] == 'paid'
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_reconnect_receiver_fulfill(node_factory):
# Ordering matters: after +WIRE_UPDATE_FULFILL_HTLC, channeld
# will continue and try to send WIRE_COMMITMENT_SIGNED: if
# that's the next failure, it will do two in one run.
disconnects = ['@WIRE_UPDATE_FULFILL_HTLC',
'+WIRE_UPDATE_FULFILL_HTLC',
'-WIRE_UPDATE_FULFILL_HTLC',
'-WIRE_COMMITMENT_SIGNED',
'@WIRE_COMMITMENT_SIGNED',
'+WIRE_COMMITMENT_SIGNED',
'-WIRE_REVOKE_AND_ACK',
'@WIRE_REVOKE_AND_ACK',
'+WIRE_REVOKE_AND_ACK']
l1 = node_factory.get_node(may_reconnect=True)
l2 = node_factory.get_node(disconnect=disconnects,
may_reconnect=True)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.fund_channel(l2, 10**6)
amt = 200000000
rhash = l2.rpc.invoice(amt, 'testpayment2', 'desc')['payment_hash']
assert only_one(l2.rpc.listinvoices('testpayment2')['invoices'])['status'] == 'unpaid'
route = [{'msatoshi': amt, 'id': l2.info['id'], 'delay': 5, 'channel': '1x1x1'}]
l1.rpc.sendpay(route, rhash)
for i in range(len(disconnects)):
l1.daemon.wait_for_log('Already have funding locked in')
assert only_one(l2.rpc.listinvoices('testpayment2')['invoices'])['status'] == 'paid'
@flaky
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_shutdown_reconnect(node_factory):
disconnects = ['-WIRE_SHUTDOWN',
'@WIRE_SHUTDOWN',
'+WIRE_SHUTDOWN']
l1 = node_factory.get_node(disconnect=disconnects,
may_reconnect=True)
l2 = node_factory.get_node(may_reconnect=True)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
chan = l1.fund_channel(l2, 10**6)
l1.pay(l2, 200000000)
assert l1.bitcoin.rpc.getmempoolinfo()['size'] == 0
# This should wait until we're closed.
l1.rpc.close(chan)
l1.daemon.wait_for_log(' to CHANNELD_SHUTTING_DOWN')
l2.daemon.wait_for_log(' to CHANNELD_SHUTTING_DOWN')
l1.daemon.wait_for_log(' to CLOSINGD_SIGEXCHANGE')
l2.daemon.wait_for_log(' to CLOSINGD_SIGEXCHANGE')
# And should put closing into mempool (happens async, so
# CLOSINGD_COMPLETE may come first).
l1.daemon.wait_for_logs(['sendrawtx exit 0', ' to CLOSINGD_COMPLETE'])
l2.daemon.wait_for_logs(['sendrawtx exit 0', ' to CLOSINGD_COMPLETE'])
assert l1.bitcoin.rpc.getmempoolinfo()['size'] == 1
@flaky
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_reconnect_remote_sends_no_sigs(node_factory):
"""We re-announce, even when remote node doesn't send its announcement_signatures on reconnect.
"""
l1, l2 = node_factory.line_graph(2, wait_for_announce=True, opts={'may_reconnect': True})
# When l1 restarts (with rescan=1), make it think it hasn't
# reached announce_depth, so it wont re-send announcement_signatures
def no_blocks_above(req):
if req['params'][0] > 107:
return {"result": None,
"error": {"code": -8, "message": "Block height out of range"}, "id": req['id']}
else:
return {'result': l1.bitcoin.rpc.getblockhash(req['params'][0]),
"error": None, 'id': req['id']}
l1.daemon.rpcproxy.mock_rpc('getblockhash', no_blocks_above)
l1.restart()
# l2 will now uses (REMOTE's) announcement_signatures it has stored
wait_for(lambda: only_one(l2.rpc.listpeers()['peers'][0]['channels'])['status'] == [
'CHANNELD_NORMAL:Reconnected, and reestablished.',
'CHANNELD_NORMAL:Funding transaction locked. Channel announced.'])
# But l2 still sends its own sigs on reconnect
l2.daemon.wait_for_logs([r'peer_out WIRE_ANNOUNCEMENT_SIGNATURES',
r'peer_out WIRE_ANNOUNCEMENT_SIGNATURES'])
# l1 only did send them the first time
assert(''.join(l1.daemon.logs).count(r'peer_out WIRE_ANNOUNCEMENT_SIGNATURES') == 1)
def test_shutdown_awaiting_lockin(node_factory, bitcoind):
l1 = node_factory.get_node()
l2 = node_factory.get_node(options={'funding-confirms': 3})
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.fundwallet(10**6 + 1000000)
chanid = l1.rpc.fundchannel(l2.info['id'], 10**6)['channel_id']
# Technically, this is async to fundchannel.
l1.daemon.wait_for_log('sendrawtx exit 0')
bitcoind.generate_block(1)
l1.rpc.close(chanid)
l1.daemon.wait_for_log('CHANNELD_AWAITING_LOCKIN to CHANNELD_SHUTTING_DOWN')
l2.daemon.wait_for_log('CHANNELD_AWAITING_LOCKIN to CHANNELD_SHUTTING_DOWN')
l1.daemon.wait_for_log('CHANNELD_SHUTTING_DOWN to CLOSINGD_SIGEXCHANGE')
l2.daemon.wait_for_log('CHANNELD_SHUTTING_DOWN to CLOSINGD_SIGEXCHANGE')
# And should put closing into mempool (happens async, so
# CLOSINGD_COMPLETE may come first).
l1.daemon.wait_for_logs(['sendrawtx exit 0', ' to CLOSINGD_COMPLETE'])
l2.daemon.wait_for_logs(['sendrawtx exit 0', ' to CLOSINGD_COMPLETE'])
assert bitcoind.rpc.getmempoolinfo()['size'] == 1
bitcoind.generate_block(1)
l1.daemon.wait_for_log(' to ONCHAIN')
l2.daemon.wait_for_log(' to ONCHAIN')
bitcoind.generate_block(100)
wait_for(lambda: l1.rpc.listpeers()['peers'] == [])
wait_for(lambda: l2.rpc.listpeers()['peers'] == [])
def test_funding_change(node_factory, bitcoind):
"""Add some funds, fund a channel, and make sure we remember the change
"""
l1, l2 = node_factory.line_graph(2, fundchannel=False)
l1.fundwallet(10000000)
bitcoind.generate_block(1)
sync_blockheight(bitcoind, [l1])
outputs = l1.db_query('SELECT value FROM outputs WHERE status=0;')
assert only_one(outputs)['value'] == 10000000
l1.rpc.fundchannel(l2.info['id'], 1000000)
outputs = {r['status']: r['value'] for r in l1.db_query(
'SELECT status, SUM(value) AS value FROM outputs GROUP BY status;')}
# The 10m out is spent and we have a change output of 9m-fee
assert outputs[0] > 8990000
assert outputs[2] == 10000000
def test_funding_all(node_factory, bitcoind):
"""Add some funds, fund a channel using all funds, make sure no funds remain
"""
l1, l2 = node_factory.line_graph(2, fundchannel=False)
l1.fundwallet(0.1 * 10**8)
bitcoind.generate_block(1)
sync_blockheight(bitcoind, [l1])
outputs = l1.db_query('SELECT value FROM outputs WHERE status=0;')
assert only_one(outputs)['value'] == 10000000
l1.rpc.fundchannel(l2.info['id'], "all")
outputs = l1.db_query('SELECT value FROM outputs WHERE status=0;')
assert len(outputs) == 0
def test_funding_all_too_much(node_factory):
"""Add more than max possible funds, fund a channel using all funds we can.
"""
l1, l2 = node_factory.line_graph(2, fundchannel=False)
l1.fundwallet(2**24 + 10000)
l1.rpc.fundchannel(l2.info['id'], "all")
assert only_one(l1.rpc.listfunds()['outputs'])['status'] == 'unconfirmed'
assert only_one(l1.rpc.listfunds()['channels'])['channel_total_sat'] == 2**24 - 1
def test_funding_fail(node_factory, bitcoind):
"""Add some funds, fund a channel without enough funds"""
# Previous runs with same bitcoind can leave funds!
max_locktime = 5 * 6 * 24
l1 = node_factory.get_node(random_hsm=True, options={'max-locktime-blocks': max_locktime})
l2 = node_factory.get_node(options={'watchtime-blocks': max_locktime + 1})
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
funds = 1000000
addr = l1.rpc.newaddr()['bech32']
l1.bitcoin.rpc.sendtoaddress(addr, funds / 10**8)
bitcoind.generate_block(1)
# Wait for it to arrive.
wait_for(lambda: len(l1.rpc.listfunds()['outputs']) > 0)
# Fail because l1 dislikes l2's huge locktime.
with pytest.raises(RpcError, match=r'to_self_delay \d+ larger than \d+'):
l1.rpc.fundchannel(l2.info['id'], int(funds / 10))
assert only_one(l1.rpc.listpeers()['peers'])['connected']
assert only_one(l2.rpc.listpeers()['peers'])['connected']
# Restart l2 without ridiculous locktime.
del l2.daemon.opts['watchtime-blocks']
l2.restart()
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
# We don't have enough left to cover fees if we try to spend it all.
with pytest.raises(RpcError, match=r'Cannot afford transaction'):
l1.rpc.fundchannel(l2.info['id'], funds)
# Should still be connected.
assert only_one(l1.rpc.listpeers()['peers'])['connected']
l2.daemon.wait_for_log('lightning_openingd-.*: Handed peer, entering loop')
assert only_one(l2.rpc.listpeers()['peers'])['connected']
# This works.
l1.rpc.fundchannel(l2.info['id'], int(funds / 10))
def test_funding_toolarge(node_factory, bitcoind):
"""Try to create a giant channel"""
l1 = node_factory.get_node()
l2 = node_factory.get_node()
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
# Send funds.
amount = 2**24
bitcoind.rpc.sendtoaddress(l1.rpc.newaddr()['bech32'], amount / 10**8 + 0.01)
bitcoind.generate_block(1)
# Wait for it to arrive.
wait_for(lambda: len(l1.rpc.listfunds()['outputs']) > 0)
# Fail to open (too large)
with pytest.raises(RpcError, match=r'Amount exceeded 16777215'):
l1.rpc.fundchannel(l2.info['id'], amount)
# This should work.
amount = amount - 1
l1.rpc.fundchannel(l2.info['id'], amount)
def test_funding_by_utxos(node_factory, bitcoind):
"""Fund a channel with specific utxos"""
l1, l2, l3 = node_factory.line_graph(3, fundchannel=False)
# Get 3 differents utxo
l1.fundwallet(0.01 * 10**8)
l1.fundwallet(0.01 * 10**8)
l1.fundwallet(0.01 * 10**8)
wait_for(lambda: len(l1.rpc.listfunds()["outputs"]) == 3)
utxos = [utxo["txid"] + ":" + str(utxo["output"]) for utxo in l1.rpc.listfunds()["outputs"]]
# Fund with utxos we don't own
with pytest.raises(RpcError, match=r"No matching utxo was found from the wallet"):
l3.rpc.fundchannel(l2.info["id"], int(0.01 * 10**8), utxos=utxos)
# Fund with an empty array
with pytest.raises(RpcError, match=r"Please specify an array of \\'txid:output_index\\', not \"*\""):
l1.rpc.fundchannel(l2.info["id"], int(0.01 * 10**8), utxos=[])
# Fund a channel from some of the utxos, without change
l1.rpc.fundchannel(l2.info["id"], "all", utxos=utxos[0:2])
# Fund a channel from the rest of utxos, with change
l1.rpc.connect(l3.info["id"], "localhost", l3.port)
l1.rpc.fundchannel(l3.info["id"], int(0.007 * 10**8), utxos=[utxos[2]])
# Fund another channel with already spent utxos
with pytest.raises(RpcError, match=r"No matching utxo was found from the wallet"):
l1.rpc.fundchannel(l3.info["id"], int(0.01 * 10**8), utxos=utxos)
def test_funding_external_wallet_corners(node_factory, bitcoind):
l1 = node_factory.get_node()
l2 = node_factory.get_node()
amount = 2**24
# Fail to open (too large)
with pytest.raises(RpcError, match=r'Amount exceeded 16777215'):
l1.rpc.fundchannel_start(l2.info['id'], amount)
amount = amount - 1
fake_txid = '929764844a8f9938b669a60a1d51a11c9e2613c7eb4776e4126f1f20c0a685c3'
fake_txout = 0
with pytest.raises(RpcError, match=r'Unknown peer'):
l1.rpc.fundchannel_start(l2.info['id'], amount)
with pytest.raises(RpcError, match=r'Unknown peer'):
l1.rpc.fundchannel_complete(l2.info['id'], fake_txid, fake_txout)
# Should not be able to continue without being in progress.
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
with pytest.raises(RpcError, match=r'No channel funding in progress.'):
l1.rpc.fundchannel_complete(l2.info['id'], fake_txid, fake_txout)
l1.rpc.fundchannel_start(l2.info['id'], amount)
with pytest.raises(RpcError, match=r'Already funding channel'):
l1.rpc.fundchannel(l2.info['id'], amount)
l1.rpc.fundchannel_cancel(l2.info['id'])
# Should be able to 'restart' after canceling
l1.rpc.fundchannel_start(l2.info['id'], amount)
def test_funding_cancel_race(node_factory, bitcoind, executor):
l1 = node_factory.get_node()
if VALGRIND or SLOW_MACHINE:
num = 5
else:
num = 100
nodes = node_factory.get_nodes(num)
# Speed up cleanup by not cleaning our test nodes: on my laptop, this goes
# from 214 to 15 seconds
node_factory.nodes = [l1]
num_complete = 0
num_cancel = 0
for count, n in enumerate(nodes):
l1.rpc.connect(n.info['id'], 'localhost', n.port)
l1.rpc.fundchannel_start(n.info['id'], "100000sat")
# We simply make up txids. And submit two of each at once.
completes = []
cancels = []
# Switch order around.
for i in range(4):
if (i + count) % 2 == 0:
completes.append(executor.submit(l1.rpc.fundchannel_complete, n.info['id'], "9f1844419d2f41532a57fb5ef038cacb602000f7f37b3dae68dc2d047c89048f", 0))
else:
cancels.append(executor.submit(l1.rpc.fundchannel_cancel, n.info['id']))
# Only one should succeed.
success = False
for c in completes:
try:
c.result(TIMEOUT)
num_complete += 1
assert not success
success = True
except RpcError:
pass
# These may both succeed, iff the above didn't.
cancelled = False
for c in cancels:
try:
c.result(TIMEOUT)
cancelled = True
assert not success
except RpcError:
pass
if cancelled:
num_cancel += 1
else:
assert success
print("Cancelled {} complete {}".format(num_cancel, num_complete))
assert num_cancel + num_complete == len(nodes)
# We should have raced at least once!
if not VALGRIND:
assert num_cancel > 0
assert num_complete > 0
def test_funding_external_wallet(node_factory, bitcoind):
l1 = node_factory.get_node()
l2 = node_factory.get_node()
l3 = node_factory.get_node()
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
assert(l1.rpc.listpeers()['peers'][0]['id'] == l2.info['id'])
amount = 2**24 - 1
address = l1.rpc.fundchannel_start(l2.info['id'], amount)['funding_address']
assert len(address) > 0
peer = l1.rpc.listpeers()['peers'][0]
# Peer should still be connected and in state waiting for funding_txid
assert peer['id'] == l2.info['id']
r = re.compile('Funding channel start: awaiting funding_txid with output to .*')
assert any(r.match(line) for line in peer['channels'][0]['status'])
assert 'OPENINGD' in peer['channels'][0]['state']
# Trying to start a second funding should not work, it's in progress.
with pytest.raises(RpcError, match=r'Already funding channel'):
l1.rpc.fundchannel_start(l2.info['id'], amount)
# 'Externally' fund the address from fundchannel_start
addr_scriptpubkey = bitcoind.rpc.getaddressinfo(address)['scriptPubKey']
txout = CMutableTxOut(amount, bytearray.fromhex(addr_scriptpubkey))
unfunded_tx = CMutableTransaction([], [txout])
hextx = binascii.hexlify(unfunded_tx.serialize()).decode('utf8')
funded_tx_obj = bitcoind.rpc.fundrawtransaction(hextx)
raw_funded_tx = funded_tx_obj['hex']
txid = bitcoind.rpc.decoderawtransaction(raw_funded_tx)['txid']
txout = 1 if funded_tx_obj['changepos'] == 0 else 0
assert l1.rpc.fundchannel_complete(l2.info['id'], txid, txout)['commitments_secured']
# Broadcast the transaction manually and confirm that channel locks in
signed_tx = bitcoind.rpc.signrawtransactionwithwallet(raw_funded_tx)['hex']
assert txid == bitcoind.rpc.decoderawtransaction(signed_tx)['txid']
bitcoind.rpc.sendrawtransaction(signed_tx)
bitcoind.generate_block(1)
l1.daemon.wait_for_log(r'Funding tx {} depth 1 of 1'.format(txid))
for node in [l1, l2]:
node.daemon.wait_for_log(r'State changed from CHANNELD_AWAITING_LOCKIN to CHANNELD_NORMAL')
channel = node.rpc.listpeers()['peers'][0]['channels'][0]
assert amount * 1000 == channel['msatoshi_total']
# Test that we don't crash if peer disconnects after fundchannel_start
l2.connect(l3)
l2.rpc.fundchannel_start(l3.info["id"], amount)
l3.rpc.close(l2.info["id"])
def test_lockin_between_restart(node_factory, bitcoind):
l1 = node_factory.get_node(may_reconnect=True)
l2 = node_factory.get_node(options={'funding-confirms': 3},
may_reconnect=True)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.fundwallet(10**6 + 1000000)
l1.rpc.fundchannel(l2.info['id'], 10**6)['tx']
# l1 goes down.
l1.stop()
# Now 120 blocks go by...
bitcoind.generate_block(120)
# Restart
l1.start()
# All should be good.
l1.daemon.wait_for_log(' to CHANNELD_NORMAL')
l2.daemon.wait_for_log(' to CHANNELD_NORMAL')
def test_funding_while_offline(node_factory, bitcoind):
l1 = node_factory.get_node()
addr = l1.rpc.newaddr()['bech32']
sync_blockheight(bitcoind, [l1])
# l1 goes down.
l1.stop()
# We send funds
bitcoind.rpc.sendtoaddress(addr, (10**6 + 1000000) / 10**8)
# Now 120 blocks go by...
bitcoind.generate_block(120)
# Restart
l1.start()
sync_blockheight(bitcoind, [l1])
assert len(l1.rpc.listfunds()['outputs']) == 1
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_channel_persistence(node_factory, bitcoind, executor):
# Start two nodes and open a channel (to remember). l2 will
# mysteriously die while committing the first HTLC so we can
# check that HTLCs reloaded from the DB work.
# Feerates identical so we don't get gratuitous commit to update them
l1 = node_factory.get_node(may_reconnect=True, feerates=(7500, 7500, 7500))
l2 = node_factory.get_node(disconnect=['=WIRE_COMMITMENT_SIGNED-nocommit'],
may_reconnect=True)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
# Neither node should have a channel open, they are just connected
for n in (l1, l2):
assert(n.db_query('SELECT COUNT(id) as count FROM channels;')[0]['count'] == 0)
l1.fund_channel(l2, 100000)
peers = l1.rpc.listpeers()['peers']
assert(only_one(peers[0]['channels'])['state'] == 'CHANNELD_NORMAL')
# Both nodes should now have exactly one channel in the database
for n in (l1, l2):
assert(n.db_query('SELECT COUNT(id) as count FROM channels;')[0]['count'] == 1)
# Fire off a sendpay request, it'll get interrupted by a restart
executor.submit(l1.pay, l2, 10000)
# Wait for it to be committed to, i.e., stored in the DB
l1.daemon.wait_for_log('peer_in WIRE_COMMITMENT_SIGNED')
# Stop l2, l1 will reattempt to connect
print("Killing l2 in mid HTLC")
l2.daemon.kill()
# Clear the disconnect and timer stop so we can proceed normally
del l2.daemon.opts['dev-disconnect']
# Wait for l1 to notice
wait_for(lambda: 'connected' not in only_one(l1.rpc.listpeers()['peers'][0]['channels']))
# Now restart l2 and it should reload peers/channels from the DB
l2.start()
wait_for(lambda: len(l2.rpc.listpeers()['peers']) == 1)
# Wait for the restored HTLC to finish
wait_for(lambda: only_one(l1.rpc.listpeers()['peers'][0]['channels'])['msatoshi_to_us'] == 99990000)
wait_for(lambda: len([p for p in l1.rpc.listpeers()['peers'] if p['connected']]))
wait_for(lambda: len([p for p in l2.rpc.listpeers()['peers'] if p['connected']]))
# Now make sure this is really functional by sending a payment
l1.pay(l2, 10000)
# L1 doesn't actually update msatoshi_to_us until it receives
# revoke_and_ack from L2, which can take a little bit.
wait_for(lambda: only_one(l1.rpc.listpeers()['peers'][0]['channels'])['msatoshi_to_us'] == 99980000)
assert only_one(l2.rpc.listpeers()['peers'][0]['channels'])['msatoshi_to_us'] == 20000
# Finally restart l1, and make sure it remembers
l1.restart()
assert only_one(l1.rpc.listpeers()['peers'][0]['channels'])['msatoshi_to_us'] == 99980000
# Now make sure l1 is watching for unilateral closes
l2.rpc.dev_fail(l1.info['id'])
l2.daemon.wait_for_log('Failing due to dev-fail command')
l2.wait_for_channel_onchain(l1.info['id'])
bitcoind.generate_block(1)
# L1 must notice.
l1.daemon.wait_for_log(' to ONCHAIN')
@unittest.skipIf(not DEVELOPER, "gossip without DEVELOPER=1 is slow")
def test_private_channel(node_factory):
l1, l2 = node_factory.line_graph(2, announce_channels=False, wait_for_announce=False)
l3, l4 = node_factory.line_graph(2, announce_channels=True, wait_for_announce=True)
assert l1.daemon.is_in_log('Will open private channel with node {}'.format(l2.info['id']))
assert not l2.daemon.is_in_log('Will open private channel with node {}'.format(l1.info['id']))
assert not l3.daemon.is_in_log('Will open private channel with node {}'.format(l4.info['id']))
l3.daemon.wait_for_log('Received node_announcement for node {}'.format(l4.info['id']))
l4.daemon.wait_for_log('Received node_announcement for node {}'.format(l3.info['id']))
assert not l1.daemon.is_in_log('Received node_announcement for node {}'.format(l2.info['id']))
assert not l2.daemon.is_in_log('Received node_announcement for node {}'.format(l1.info['id']))
# test for 'private' flag in rpc output
assert only_one(only_one(l1.rpc.listpeers(l2.info['id'])['peers'])['channels'])['private']
# check non-private channel
assert not only_one(only_one(l4.rpc.listpeers(l3.info['id'])['peers'])['channels'])['private']
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1 for --dev-broadcast-interval")
def test_channel_reenable(node_factory):
l1, l2 = node_factory.line_graph(2, opts={'may_reconnect': True}, fundchannel=True, wait_for_announce=True)
l1.daemon.wait_for_log('Received node_announcement for node {}'.format(l2.info['id']))
l2.daemon.wait_for_log('Received node_announcement for node {}'.format(l1.info['id']))
# Both directions should be active before the restart
wait_for(lambda: [c['active'] for c in l1.rpc.listchannels()['channels']] == [True, True])
# Restart l2, will cause l1 to reconnect
l2.stop()
wait_for(lambda: [c['active'] for c in l1.rpc.listchannels()['channels']] == [False, False])
l2.start()
# Updates may be suppressed if redundant; just test results.
wait_for(lambda: [c['active'] for c in l1.rpc.listchannels()['channels']] == [True, True])
wait_for(lambda: [c['active'] for c in l2.rpc.listchannels()['channels']] == [True, True])
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_update_fee(node_factory, bitcoind):
l1, l2 = node_factory.line_graph(2, fundchannel=True)
chanid = l1.get_channel_scid(l2)
# Make l1 send out feechange.
l1.set_feerates((14000, 7500, 3750))
l2.daemon.wait_for_log('peer updated fee to 14000')
# Now make sure an HTLC works.
# (First wait for route propagation.)
l1.wait_channel_active(chanid)
sync_blockheight(bitcoind, [l1, l2])
# Make payments.
l1.pay(l2, 200000000)
l2.pay(l1, 100000000)
# Now shutdown cleanly.
l1.rpc.close(chanid)
l1.daemon.wait_for_log(' to CLOSINGD_COMPLETE')
l2.daemon.wait_for_log(' to CLOSINGD_COMPLETE')
# And should put closing into mempool.
l1.wait_for_channel_onchain(l2.info['id'])
l2.wait_for_channel_onchain(l1.info['id'])
bitcoind.generate_block(1)
l1.daemon.wait_for_log(' to ONCHAIN')
l2.daemon.wait_for_log(' to ONCHAIN')
bitcoind.generate_block(99)
l1.daemon.wait_for_log('onchaind complete, forgetting peer')
l2.daemon.wait_for_log('onchaind complete, forgetting peer')
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_fee_limits(node_factory):
l1, l2 = node_factory.line_graph(2, opts={'dev-max-fee-multiplier': 5, 'may_reconnect': True}, fundchannel=True)
# L1 asks for stupid low fee (will actually hit the floor of 253)
l1.stop()
l1.set_feerates((15, 15, 15), False)
l1.start()
l1.daemon.wait_for_log('Peer permanent failure in CHANNELD_NORMAL: lightning_channeld: received ERROR channel .*: update_fee 253 outside range 1875-75000')
# Make sure the resolution of this one doesn't interfere with the next!
# Note: may succeed, may fail with insufficient fee, depending on how
# bitcoind feels!
l1.daemon.wait_for_log('sendrawtx exit')
# Trying to open a channel with too low a fee-rate is denied
l4 = node_factory.get_node()
l1.rpc.connect(l4.info['id'], 'localhost', l4.port)
with pytest.raises(RpcError, match='They sent error .* feerate_per_kw 253 below minimum'):
l1.fund_channel(l4, 10**6)
# Restore to normal.
l1.stop()
l1.set_feerates((15000, 7500, 3750), False)
l1.start()
# Try with node which sets --ignore-fee-limits
l3 = node_factory.get_node(options={'ignore-fee-limits': 'true'}, may_reconnect=True)
l1.rpc.connect(l3.info['id'], 'localhost', l3.port)
chan = l1.fund_channel(l3, 10**6)
# Try stupid high fees
l1.stop()
l1.set_feerates((15000 * 10, 7500, 3750), False)
l1.start()
l3.daemon.wait_for_log('peer_in WIRE_UPDATE_FEE')
l3.daemon.wait_for_log('peer_in WIRE_COMMITMENT_SIGNED')
# We need to wait until both have committed and revoked the
# old state, otherwise we'll still try to commit with the old
# 15sat/byte fee
l1.daemon.wait_for_log('peer_out WIRE_REVOKE_AND_ACK')
# This should wait for close to complete
l1.rpc.close(chan)
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_update_fee_reconnect(node_factory, bitcoind):
# Disconnect after first commitsig.
disconnects = ['+WIRE_COMMITMENT_SIGNED']
# Feerates identical so we don't get gratuitous commit to update them
l1 = node_factory.get_node(disconnect=disconnects, may_reconnect=True,
feerates=(15000, 15000, 3750))
# We match l2's later feerate, so we agree on same closing tx for simplicity.
l2 = node_factory.get_node(may_reconnect=True,
feerates=(14000, 14000, 3750))
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
chan = l1.fund_channel(l2, 10**6)
# Make l1 send out feechange; triggers disconnect/reconnect.
# (Note: < 10% change, so no smoothing here!)
l1.set_feerates((14000, 14000, 3750))
l1.daemon.wait_for_log('Setting REMOTE feerate to 14000')
l2.daemon.wait_for_log('Setting LOCAL feerate to 14000')
l1.daemon.wait_for_log(r'dev_disconnect: \+WIRE_COMMITMENT_SIGNED')
# Wait for reconnect....
l1.daemon.wait_for_log('Applying feerate 14000 to LOCAL')
l1.pay(l2, 200000000)
l2.pay(l1, 100000000)
# They should both have gotten commits with correct feerate.
assert l1.daemon.is_in_log('got commitsig [0-9]*: feerate 14000')
assert l2.daemon.is_in_log('got commitsig [0-9]*: feerate 14000')
# Now shutdown cleanly.
l1.rpc.close(chan)
# And should put closing into mempool.
l1.wait_for_channel_onchain(l2.info['id'])
l2.wait_for_channel_onchain(l1.info['id'])
bitcoind.generate_block(1)
l1.daemon.wait_for_log(' to ONCHAIN')
l2.daemon.wait_for_log(' to ONCHAIN')
bitcoind.generate_block(99)
l1.daemon.wait_for_log('onchaind complete, forgetting peer')
l2.daemon.wait_for_log('onchaind complete, forgetting peer')
@unittest.skipIf(not DEVELOPER, "Too slow without --dev-bitcoind-poll")
def test_multiple_channels(node_factory):
l1 = node_factory.get_node()
l2 = node_factory.get_node()
for i in range(3):
# FIXME: we shouldn't disconnect on close?
ret = l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
assert ret['id'] == l2.info['id']
l1.daemon.wait_for_log('openingd-.*: Handed peer, entering loop')
l2.daemon.wait_for_log('openingd-.*: Handed peer, entering loop')
chan = l1.fund_channel(l2, 10**6)
l1.rpc.close(chan)
channels = only_one(l1.rpc.listpeers()['peers'])['channels']
assert len(channels) == 3
# Most in state ONCHAIN, last is CLOSINGD_COMPLETE
for i in range(len(channels) - 1):
assert channels[i]['state'] == 'ONCHAIN'
assert channels[-1]['state'] == 'CLOSINGD_COMPLETE'
@unittest.skipIf(not DEVELOPER, "needs DEVELOPER=1")
def test_forget_channel(node_factory):
l1 = node_factory.get_node()
l2 = node_factory.get_node()
l1.fundwallet(10**6)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.rpc.fundchannel(l2.info['id'], 10**5)
assert len(l1.rpc.listpeers()['peers']) == 1
# This should fail, the funding tx is in the mempool and may confirm
with pytest.raises(RpcError, match=r'Cowardly refusing to forget channel'):
l1.rpc.dev_forget_channel(l2.info['id'])
assert len(l1.rpc.listpeers()['peers']) == 1
# Forcing should work
l1.rpc.dev_forget_channel(l2.info['id'], True)
assert len(l1.rpc.listpeers()['peers']) == 0
# And restarting should keep that peer forgotten
l1.restart()
assert len(l1.rpc.listpeers()['peers']) == 0
# The entry in the channels table should still be there
assert l1.db_query("SELECT count(*) as c FROM channels;")[0]['c'] == 1
assert l2.db_query("SELECT count(*) as c FROM channels;")[0]['c'] == 1
def test_peerinfo(node_factory, bitcoind):
l1, l2 = node_factory.line_graph(2, fundchannel=False, opts={'may_reconnect': True})
lfeatures = 'aa'
# Gossiping but no node announcement yet
assert l1.rpc.getpeer(l2.info['id'])['connected']
assert len(l1.rpc.getpeer(l2.info['id'])['channels']) == 0
assert l1.rpc.getpeer(l2.info['id'])['localfeatures'] == lfeatures
# Fund a channel to force a node announcement
chan = l1.fund_channel(l2, 10**6)
# Now proceed to funding-depth and do a full gossip round
bitcoind.generate_block(5)
l1.daemon.wait_for_logs(['Received node_announcement for node ' + l2.info['id']])
l2.daemon.wait_for_logs(['Received node_announcement for node ' + l1.info['id']])
# Should have announced the same global features as told to peer.
nodes1 = l1.rpc.listnodes(l2.info['id'])['nodes']
nodes2 = l2.rpc.listnodes(l2.info['id'])['nodes']
peer1 = l1.rpc.getpeer(l2.info['id'])
peer2 = l2.rpc.getpeer(l1.info['id'])
assert only_one(nodes1)['globalfeatures'] == peer1['globalfeatures']
assert only_one(nodes2)['globalfeatures'] == peer2['globalfeatures']
assert l1.rpc.getpeer(l2.info['id'])['localfeatures'] == lfeatures
assert l2.rpc.getpeer(l1.info['id'])['localfeatures'] == lfeatures
# If it reconnects after db load, it should know features.
l1.restart()
wait_for(lambda: l1.rpc.getpeer(l2.info['id'])['connected'])
wait_for(lambda: l2.rpc.getpeer(l1.info['id'])['connected'])
assert l1.rpc.getpeer(l2.info['id'])['localfeatures'] == lfeatures
assert l2.rpc.getpeer(l1.info['id'])['localfeatures'] == lfeatures
# Close the channel to forget the peer
l1.rpc.close(chan)
wait_for(lambda: not only_one(l1.rpc.listpeers(l2.info['id'])['peers'])['connected'])
wait_for(lambda: not only_one(l2.rpc.listpeers(l1.info['id'])['peers'])['connected'])
bitcoind.generate_block(100)
l1.daemon.wait_for_log('onchaind complete, forgetting peer')
l2.daemon.wait_for_log('onchaind complete, forgetting peer')
# The only channel was closed, everybody should have forgotten the nodes
assert l1.rpc.listnodes()['nodes'] == []
assert l2.rpc.listnodes()['nodes'] == []
def test_disconnectpeer(node_factory, bitcoind):
l1, l2, l3 = node_factory.get_nodes(3, opts={'may_reconnect': False})
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.rpc.connect(l3.info['id'], 'localhost', l3.port)
# Gossiping
assert l1.rpc.getpeer(l2.info['id'])['connected']
assert len(l1.rpc.getpeer(l2.info['id'])['channels']) == 0
assert l1.rpc.getpeer(l3.info['id'])['connected']
assert len(l1.rpc.getpeer(l3.info['id'])['channels']) == 0
wait_for(lambda: l2.rpc.getpeer(l1.info['id']) is not None)
# Disconnect l2 from l1
l1.rpc.disconnect(l2.info['id'])
# Make sure listpeers no longer returns the disconnected node
assert l1.rpc.getpeer(l2.info['id']) is None
wait_for(lambda: l2.rpc.getpeer(l1.info['id']) is None)
# Make sure you cannot disconnect after disconnecting
with pytest.raises(RpcError, match=r'Peer not connected'):
l1.rpc.disconnect(l2.info['id'])
with pytest.raises(RpcError, match=r'Peer not connected'):
l2.rpc.disconnect(l1.info['id'])
# Fund channel l1 -> l3
l1.fund_channel(l3, 10**6)
bitcoind.generate_block(5)
# disconnecting a non gossiping peer results in error
with pytest.raises(RpcError, match=r'Peer is in state CHANNELD_NORMAL'):
l1.rpc.disconnect(l3.info['id'])
@unittest.skipIf(not DEVELOPER, "needs --dev-max-funding-unconfirmed-blocks")
def test_fundee_forget_funding_tx_unconfirmed(node_factory, bitcoind):
"""Test that fundee will forget the channel if
the funding tx has been unconfirmed for too long.
"""
# Keep this low (default is 2016), since everything
# is much slower in VALGRIND mode and wait_for_log
# could time out before lightningd processes all the
# blocks.
blocks = 200
# funder
l1 = node_factory.get_node()
# fundee
l2 = node_factory.get_node(options={"dev-max-funding-unconfirmed-blocks": blocks})
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
# Give funder some funds.
l1.fundwallet(10**7)
# Let blocks settle.
time.sleep(1)
def mock_sendrawtransaction(r):
return {'id': r['id'], 'error': {'code': 100, 'message': 'sendrawtransaction disabled'}}
# Prevent funder from broadcasting funding tx (any tx really).
l1.daemon.rpcproxy.mock_rpc('sendrawtransaction', mock_sendrawtransaction)
# Fund the channel.
# The process will complete, but funder will be unable
# to broadcast and confirm funding tx.
with pytest.raises(RpcError, match=r'sendrawtransaction disabled'):
l1.rpc.fundchannel(l2.info['id'], 10**6)
# Generate blocks until unconfirmed.
bitcoind.generate_block(blocks)
# fundee will forget channel!
l2.daemon.wait_for_log('Forgetting channel: It has been {} blocks'.format(blocks))
# fundee will also forget and disconnect from peer.
assert len(l2.rpc.listpeers(l1.info['id'])['peers']) == 0
@unittest.skipIf(not DEVELOPER, "needs dev_fail")
def test_no_fee_estimate(node_factory, bitcoind, executor):
l1 = node_factory.get_node(start=False)
# Fail any fee estimation requests until we allow them further down
l1.daemon.rpcproxy.mock_rpc('estimatesmartfee', {
'error': {"errors": ["Insufficient data or no feerate found"], "blocks": 0}
})
l1.start()
l2 = node_factory.get_node()
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
# Can't fund a channel.
l1.fundwallet(10**7)
with pytest.raises(RpcError, match=r'Cannot estimate fees'):
l1.rpc.fundchannel(l2.info['id'], 10**6)
# Can't withdraw either.
with pytest.raises(RpcError, match=r'Cannot estimate fees'):
l1.rpc.withdraw(l2.rpc.newaddr()['bech32'], 'all')
# Can't use feerate names, either.
with pytest.raises(RpcError, match=r'Cannot estimate fees'):
l1.rpc.withdraw(l2.rpc.newaddr()['bech32'], 'all', 'urgent')
l1.rpc.withdraw(l2.rpc.newaddr()['bech32'], 'all', 'normal')
l1.rpc.withdraw(l2.rpc.newaddr()['bech32'], 'all', 'slow')
with pytest.raises(RpcError, match=r'Cannot estimate fees'):
l1.rpc.fundchannel(l2.info['id'], 10**6, 'urgent')
l1.rpc.fundchannel(l2.info['id'], 10**6, 'normal')
l1.rpc.fundchannel(l2.info['id'], 10**6, 'slow')
# Can with manual feerate.
l1.rpc.withdraw(l2.rpc.newaddr()['bech32'], 10000, '1500perkb')
l1.rpc.fundchannel(l2.info['id'], 10**6, '2000perkw', minconf=0)
# Make sure we clean up cahnnel for later attempt.
l1.daemon.wait_for_log('sendrawtx exit 0')
l1.rpc.dev_fail(l2.info['id'])
l1.daemon.wait_for_log('Failing due to dev-fail command')
l1.wait_for_channel_onchain(l2.info['id'])
bitcoind.generate_block(6)
wait_for(lambda: only_one(l1.rpc.getpeer(l2.info['id'])['channels'])['state'] == 'ONCHAIN')
wait_for(lambda: only_one(l2.rpc.getpeer(l1.info['id'])['channels'])['state'] == 'ONCHAIN')
# But can accept incoming connections.
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l2.fund_channel(l1, 10**6)
# Can do HTLCs.
l2.pay(l1, 10**5)
# Can do mutual close.
l1.rpc.close(l2.info['id'])
wait_for(lambda: len(bitcoind.rpc.getrawmempool()) > 0)
bitcoind.generate_block(100)
# Can do unilateral close.
l2.rpc.connect(l1.info['id'], 'localhost', l1.port)
l2.fund_channel(l1, 10**6)
l2.pay(l1, 10**9 // 2)
l1.rpc.dev_fail(l2.info['id'])
l1.daemon.wait_for_log('Failing due to dev-fail command')
l1.wait_for_channel_onchain(l2.info['id'])
bitcoind.generate_block(5)
wait_for(lambda: len(bitcoind.rpc.getrawmempool()) > 0)
bitcoind.generate_block(100)
# Start estimatesmartfee.
l1.set_feerates((15000, 7500, 3750), True)
# Can now fund a channel (as a test, use slow feerate).
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.rpc.fundchannel(l2.info['id'], 10**6, 'slow')
# Can withdraw (use urgent feerate).
l1.rpc.withdraw(l2.rpc.newaddr()['bech32'], 'all', 'urgent')
@unittest.skipIf(not DEVELOPER, "needs --dev-disconnect")
def test_funder_feerate_reconnect(node_factory, bitcoind):
# l1 updates fees, then reconnect so l2 retransmits commitment_signed.
disconnects = ['-WIRE_COMMITMENT_SIGNED']
l1 = node_factory.get_node(may_reconnect=True,
feerates=(7500, 7500, 7500))
l2 = node_factory.get_node(disconnect=disconnects, may_reconnect=True)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.fund_channel(l2, 10**6)
# create fee update, causing disconnect.
l1.set_feerates((15000, 7500, 3750))
l2.daemon.wait_for_log(r'dev_disconnect: \-WIRE_COMMITMENT_SIGNED')
# Wait until they reconnect.
l1.daemon.wait_for_log('Peer transient failure in CHANNELD_NORMAL')
wait_for(lambda: l1.rpc.getpeer(l2.info['id'])['connected'])
# Should work normally.
l1.pay(l2, 200000000)
def test_funder_simple_reconnect(node_factory, bitcoind):
"""Sanity check that reconnection works with completely unused channels"""
# Set fees even so it doesn't send any commitments.
l1 = node_factory.get_node(may_reconnect=True,
feerates=(7500, 7500, 7500))
l2 = node_factory.get_node(may_reconnect=True)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.fund_channel(l2, 10**6)
l1.rpc.disconnect(l2.info['id'], True)
# Wait until they reconnect.
wait_for(lambda: l1.rpc.getpeer(l2.info['id'])['connected'])
# Should work normally.
l1.pay(l2, 200000000)
@unittest.skipIf(not DEVELOPER, "needs LIGHTNINGD_DEV_LOG_IO")
def test_dataloss_protection(node_factory, bitcoind):
l1 = node_factory.get_node(may_reconnect=True, log_all_io=True,
feerates=(7500, 7500, 7500))
l2 = node_factory.get_node(may_reconnect=True, log_all_io=True,
feerates=(7500, 7500, 7500), allow_broken_log=True)
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
# l1 should send out WIRE_INIT (0010)
l1.daemon.wait_for_log(r"\[OUT\] 0010"
# gflen == 0
"0000"
# lflen == 1
"0001"
# Local features 1, 3, 5 and 7 (0xaa).
"aa")
l1.fund_channel(l2, 10**6)
l2.stop()
# Save copy of the db.
dbpath = os.path.join(l2.daemon.lightning_dir, "lightningd.sqlite3")
orig_db = open(dbpath, "rb").read()
l2.start()
# l1 should have sent WIRE_CHANNEL_REESTABLISH with option_data_loss_protect.
l1.daemon.wait_for_log(r"\[OUT\] 0088"
# channel_id
"[0-9a-f]{64}"
# next_local_commitment_number
"0000000000000001"
# next_remote_revocation_number
"0000000000000000"
# your_last_per_commitment_secret (funding_depth may
# trigger a fee-update and commit, hence this may not
# be zero)
"[0-9a-f]{64}"
# my_current_per_commitment_point
"0[23][0-9a-f]{64}")
# After an htlc, we should get different results (two more commits)
l1.pay(l2, 200000000)
# Make sure both sides consider it completely settled (has received both
# REVOKE_AND_ACK)
l1.daemon.wait_for_logs([r"\[IN\] 0085"] * 2)
l2.daemon.wait_for_logs([r"\[IN\] 0085"] * 2)
l2.restart()
# l1 should have sent WIRE_CHANNEL_REESTABLISH with option_data_loss_protect.
l1.daemon.wait_for_log(r"\[OUT\] 0088"
# channel_id
"[0-9a-f]{64}"
# next_local_commitment_number
"000000000000000[1-9]"
# next_remote_revocation_number
"000000000000000[1-9]"
# your_last_per_commitment_secret
"[0-9a-f]{64}"
# my_current_per_commitment_point
"0[23][0-9a-f]{64}")
# Now, move l2 back in time.
l2.stop()
# Overwrite with OLD db.
open(dbpath, "wb").write(orig_db)
l2.start()
# l2 should freak out!
l2.daemon.wait_for_log("Peer permanent failure in CHANNELD_NORMAL: Awaiting unilateral close")
# l1 should drop to chain.
l1.wait_for_channel_onchain(l2.info['id'])
# l2 must NOT drop to chain.
l2.daemon.wait_for_log("Cannot broadcast our commitment tx: they have a future one")
assert not l2.daemon.is_in_log('sendrawtx exit 0')
closetxid = only_one(bitcoind.rpc.getrawmempool(False))
# l2 should still recover something!
bitcoind.generate_block(1)
l2.daemon.wait_for_log("ERROR: Unknown commitment #[0-9], recovering our funds!")
# Restarting l2, and it should remember from db.
l2.restart()
l2.daemon.wait_for_log("ERROR: Unknown commitment #[0-9], recovering our funds!")
bitcoind.generate_block(100)
l2.daemon.wait_for_log('onchaind complete, forgetting peer')
# l2 should have it in wallet.
assert (closetxid, "confirmed") in set([(o['txid'], o['status']) for o in l2.rpc.listfunds()['outputs']])
@unittest.skipIf(not DEVELOPER, "needs dev_disconnect")
def test_restart_multi_htlc_rexmit(node_factory, bitcoind, executor):
# l1 disables commit timer once we send first htlc, dies on commit
disconnects = ['=WIRE_UPDATE_ADD_HTLC-nocommit',
'-WIRE_COMMITMENT_SIGNED']
l1, l2 = node_factory.line_graph(2, opts=[{'disconnect': disconnects,
'may_reconnect': True},
{'may_reconnect': True}])
executor.submit(l1.pay, l2, 20000)
executor.submit(l1.pay, l2, 30000)
l1.daemon.wait_for_logs(['peer_out WIRE_UPDATE_ADD_HTLC'] * 2)
l1.rpc.dev_reenable_commit(l2.info['id'])
l1.daemon.wait_for_log('dev_disconnect: -WIRE_COMMITMENT_SIGNED')
# This will make it reconnect
l1.stop()
# Clear the disconnect so we can proceed normally
del l1.daemon.opts['dev-disconnect']
l1.start()
# Payments will fail due to restart, but we can see results in listsendpays.
print(l1.rpc.listsendpays())
wait_for(lambda: [p['status'] for p in l1.rpc.listsendpays()['payments']] == ['complete', 'complete'])
@unittest.skipIf(not DEVELOPER, "needs dev-disconnect")
def test_fulfill_incoming_first(node_factory, bitcoind):
"""Test that we handle the case where we completely resolve incoming htlc
before fulfilled outgoing htlc"""
# We agree on fee change first, then add HTLC, then remove; stop after remove.
disconnects = ['+WIRE_COMMITMENT_SIGNED*3']
# We manually reconnect l2 & l3, after 100 blocks; hence allowing manual
# reconnect, but disabling auto connect, and massive cltv so 2/3 doesn't
# time out.
l1, l2, l3 = node_factory.line_graph(3, opts=[{},
{'may_reconnect': True,
'dev-no-reconnect': None},
{'may_reconnect': True,
'dev-no-reconnect': None,
'disconnect': disconnects,
'cltv-final': 200}],
wait_for_announce=True)
# This succeeds.
l1.rpc.pay(l3.rpc.invoice(200000000, 'test_fulfill_incoming_first', 'desc')['bolt11'])
# l1 can shutdown, fine.
l1.rpc.close(l2.info['id'])
l1.wait_for_channel_onchain(l2.info['id'])
bitcoind.generate_block(100)
l2.daemon.wait_for_log('onchaind complete, forgetting peer')
# Now, l2 should restore from DB fine, even though outgoing HTLC no longer
# has an incoming.
l2.restart()
# Manually reconnect l2->l3.
l2.rpc.connect(l3.info['id'], 'localhost', l3.port)
# Fulfill should be retransmitted OK (ignored result).
l2.rpc.close(l3.info['id'])
l2.wait_for_channel_onchain(l3.info['id'])
bitcoind.generate_block(100)
l2.daemon.wait_for_log('onchaind complete, forgetting peer')
l3.daemon.wait_for_log('onchaind complete, forgetting peer')
@unittest.skipIf(not DEVELOPER, "gossip without DEVELOPER=1 is slow")
def test_restart_many_payments(node_factory):
l1 = node_factory.get_node(may_reconnect=True)
# On my laptop, these take 74 seconds and 44 seconds (with restart commented out)
if VALGRIND:
num = 2
else:
num = 5
# Nodes with channels into the main node
innodes = node_factory.get_nodes(num, opts={'may_reconnect': True})
inchans = []
for n in innodes:
n.rpc.connect(l1.info['id'], 'localhost', l1.port)
inchans.append(n.fund_channel(l1, 10**6, False))
# Nodes with channels out of the main node
outnodes = node_factory.get_nodes(len(innodes), opts={'may_reconnect': True})
outchans = []
for n in outnodes:
n.rpc.connect(l1.info['id'], 'localhost', l1.port)
outchans.append(l1.fund_channel(n, 10**6, False))
# Now do all the waiting at once: if !DEVELOPER, this can be *very* slow!
l1_logs = []
for i in range(len(innodes)):
scid = inchans[i]
l1_logs += [r'update for channel {}/0 now ACTIVE'.format(scid),
r'update for channel {}/1 now ACTIVE'.format(scid),
'to CHANNELD_NORMAL']
innodes[i].daemon.wait_for_logs([r'update for channel {}/0 now ACTIVE'
.format(scid),
r'update for channel {}/1 now ACTIVE'
.format(scid),
'to CHANNELD_NORMAL'])
for i in range(len(outnodes)):
scid = outchans[i]
l1_logs += [r'update for channel {}/0 now ACTIVE'.format(scid),
r'update for channel {}/1 now ACTIVE'.format(scid),
'to CHANNELD_NORMAL']
outnodes[i].daemon.wait_for_logs([r'update for channel {}/0 now ACTIVE'
.format(scid),
r'update for channel {}/1 now ACTIVE'
.format(scid),
'to CHANNELD_NORMAL'])
l1.daemon.wait_for_logs(l1_logs)
# Manually create routes, get invoices
Payment = namedtuple('Payment', ['innode', 'route', 'payment_hash'])
to_pay = []
for i in range(len(innodes)):
# This one will cause WIRE_INCORRECT_CLTV_EXPIRY from l1.
route = [{'msatoshi': 100001001,
'id': l1.info['id'],
'delay': 10,
'channel': inchans[i]},
{'msatoshi': 100000000,
'id': outnodes[i].info['id'],
'delay': 5,
'channel': outchans[i]}]
payment_hash = outnodes[i].rpc.invoice(100000000, "invoice", "invoice")['payment_hash']
to_pay.append(Payment(innodes[i], route, payment_hash))
# This one should be routed through to the outnode.
route = [{'msatoshi': 100001001,
'id': l1.info['id'],
'delay': 11,
'channel': inchans[i]},
{'msatoshi': 100000000,
'id': outnodes[i].info['id'],
'delay': 5,
'channel': outchans[i]}]
payment_hash = outnodes[i].rpc.invoice(100000000, "invoice2", "invoice2")['payment_hash']
to_pay.append(Payment(innodes[i], route, payment_hash))
# sendpay is async.
for p in to_pay:
p.innode.rpc.sendpay(p.route, p.payment_hash)
# Now restart l1 while traffic is flowing...
l1.restart()
# Wait for them to finish.
for n in innodes:
wait_for(lambda: 'pending' not in [p['status'] for p in n.rpc.listsendpays()['payments']])
@unittest.skipIf(not DEVELOPER, "need dev-disconnect")
def test_fail_unconfirmed(node_factory, bitcoind, executor):
"""Test that if we crash with an unconfirmed connection to a known
peer, we don't have a dangling peer in db"""
# = is a NOOP disconnect, but sets up file.
l1 = node_factory.get_node(disconnect=['=WIRE_OPEN_CHANNEL'])
l2 = node_factory.get_node()
# First one, we close by mutual agreement.
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.fund_channel(l2, 200000, wait_for_active=True)
l1.rpc.close(l2.info['id'])
# Make sure it's closed
l1.wait_for_channel_onchain(l2.info['id'])
bitcoind.generate_block(1)
l1.daemon.wait_for_log('State changed from CLOSINGD_COMPLETE to FUNDING_SPEND_SEEN')
l1.stop()
# Mangle disconnect file so this time it blackholes....
with open(l1.daemon.disconnect_file, "w") as f:
f.write("0WIRE_OPEN_CHANNEL\n")
l1.start()
# Now we establish a new channel, which gets stuck.
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.fundwallet(10**7)
executor.submit(l1.rpc.fundchannel, l2.info['id'], 100000)
l1.daemon.wait_for_log("dev_disconnect")
# Now complete old channel.
bitcoind.generate_block(100)
l1.daemon.wait_for_log('onchaind complete, forgetting peer')
# And crash l1, which is stuck.
l1.daemon.kill()
# Now, restart and see if it can connect OK.
del l1.daemon.opts['dev-disconnect']
l1.start()
l1.rpc.connect(l2.info['id'], 'localhost', l2.port)
l1.fund_channel(l2, 200000, wait_for_active=True)
def test_change_chaining(node_factory, bitcoind):
"""Test change chaining of unconfirmed fundings
Change chaining is the case where one transaction is broadcast but not
confirmed yet and we already build a followup on top of the change. If the
first transaction doesn't confirm we may end up creating a series of
unconfirmable transactions. This is why we generally disallow chaining.
"""
l1, l2, l3 = node_factory.get_nodes(3)
l1.fundwallet(10**8) # This will create an output with 1 confirmation
# Now fund a channel from l1 to l2, that should succeed, with minconf=1 but not before
l1.connect(l2)
with pytest.raises(RpcError):
l1.rpc.fundchannel(l2.info['id'], 10**7, minconf=2)
l1.rpc.fundchannel(l2.info['id'], 10**7) # Defaults to minconf=1
# We don't have confirmed outputs anymore, so this should fail without minconf=0
l1.connect(l3)
with pytest.raises(RpcError):
l1.rpc.fundchannel(l3.info['id'], 10**7) # Defaults to minconf=1
l1.rpc.fundchannel(l3.info['id'], 10**7, minconf=0)
def test_feerate_spam(node_factory):
l1, l2 = node_factory.line_graph(2)
# Pay almost everything to l2.
l1.pay(l2, 10**9 - 25000000)
# It will send this once (may have happened before line_graph's wait)
wait_for(lambda: l1.daemon.is_in_log('Setting REMOTE feerate to 15000'))
wait_for(lambda: l1.daemon.is_in_log('peer_out WIRE_UPDATE_FEE'))
# Now change feerates to something l1 can't afford.
l1.set_feerates((100000, 100000, 100000))
# It will raise as far as it can (20000)
l1.daemon.wait_for_log('Setting REMOTE feerate to 20000')
l1.daemon.wait_for_log('peer_out WIRE_UPDATE_FEE')
# But it won't do it again once it's at max.
with pytest.raises(TimeoutError):
l1.daemon.wait_for_log('peer_out WIRE_UPDATE_FEE', timeout=5)
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